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22 Apr 2021, 03:00
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
85% (01:43) correct
15%
(01:59)
wrong
based on 111
sessions
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What is the largest number which when divides 63, 77 and 112 leaves 3, 5 and 4 as remainders, respectively?
(A) 12
(B) 24
(C) 36
(D) 48
(E) 60
(A) 12
(B) 24
(C) 36
(D) 48
(E) 60
23 Apr 2021, 05:32
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To find
Approach and Working out:
Thus, we can say that 60, 72, and 108 is divisible by the number and we have to find the largest value of such number.
GCD = \(2^2\) × 3 = 12
Hence, option A is the correct answer.
Correct Answer: Option A
- • the largest number which when divides 63, 77 and 112 leaves 3, 5 and 4 as remainders, respectively.
Approach and Working out:
- • The remainder when 63 is divided by a number is 3.
- o Thus, 60 is divisible by the number.
- o Thus, 72 is also divisible by the number.
- o Thus, 108 is also divisible by the number.
Thus, we can say that 60, 72, and 108 is divisible by the number and we have to find the largest value of such number.
- • The greatest number that divided 2 or more than 2 number is GCD of the number.
- • 60 = \(2^2\) × 3 × 5
• 72 =\(2^2\) × \(3^2\)
• 108 = \(2^2\) × \(3^3\)
GCD = \(2^2\) × 3 = 12
Hence, option A is the correct answer.
Correct Answer: Option A
24 Apr 2021, 13:57
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What is the largest number which when divides 63, 77 and 112 leaves 3, 5 and 4 as remainders, respectively?
So, the divisible nos. are 63-3 =60, 77-5 = 72 and 112-4 = 108 and their HCF = 12
So, I think A.
So, the divisible nos. are 63-3 =60, 77-5 = 72 and 112-4 = 108 and their HCF = 12
So, I think A.
