Summer is Coming! Join the Game of Timers Competition to Win Epic Prizes. Registration is Open. Game starts Mon July 1st.

It is currently 19 Jul 2019, 16:45

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel

What is the largest possible value of y if (x+3)^2 + (y+6)^2 = 100?

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:

Hide Tags

Find Similar Topics 
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 56300
What is the largest possible value of y if (x+3)^2 + (y+6)^2 = 100?  [#permalink]

Show Tags

New post 22 Aug 2018, 00:49
00:00
A
B
C
D
E

Difficulty:

  15% (low)

Question Stats:

76% (01:19) correct 24% (01:58) wrong based on 69 sessions

HideShow timer Statistics


NUS School Moderator
User avatar
D
Joined: 18 Jul 2018
Posts: 985
Location: India
Concentration: Finance, Marketing
WE: Engineering (Energy and Utilities)
Premium Member Reviews Badge CAT Tests
Re: What is the largest possible value of y if (x+3)^2 + (y+6)^2 = 100?  [#permalink]

Show Tags

New post 22 Aug 2018, 01:00
Let's consider X = -3. Then the max value of Y can be 4.

B is the answer.

Posted from my mobile device
_________________
Press +1 Kudos If my post helps!
e-GMAT Representative
User avatar
V
Joined: 04 Jan 2015
Posts: 2943
What is the largest possible value of y if (x+3)^2 + (y+6)^2 = 100?  [#permalink]

Show Tags

New post 22 Aug 2018, 01:02

Solution



Given:
    • Two variables x and y
    • \((x+3)^2 + (y+6)^2 = 100\)

To find:
    • Largest possible value of y

Approach and Working:
If y is largest, then \((y+6)^2\) must be largest, and simultaneously \((x+3)^2\) must be smallest.
    • Now, the minimum value of any square number is always 0.
      o Hence, if y is largest, we can say \((x+3)^2\) is 0.
      o Therefore, \((y+6)^2 = 100 = 10^2\)
      Or, y + 6 = 10 (ignoring the negative root, as we are maximising y)
      Or, y = 4

Hence, the correct answer is option B.

Answer: B

Image

_________________
VP
VP
User avatar
D
Joined: 31 Oct 2013
Posts: 1392
Concentration: Accounting, Finance
GPA: 3.68
WE: Analyst (Accounting)
What is the largest possible value of y if (x+3)^2 + (y+6)^2 = 100?  [#permalink]

Show Tags

New post 22 Aug 2018, 01:20
Bunuel wrote:
What is the largest possible value of y if (x+3)^2 + (y+6)^2 = 100?

A. -2
B. 4
C. 5
D. 8
E. 12



Given

\((x+3)^2 + (y+6)^2 = 100\)

we are looking for the largest value of y. Therefore we need to minimize \((x + 3)^2\). x can be anything as there are no conditions related to x are given. any value other than - 3 is not accepted in this case.

\((- 3 + 3 )^2 + (y + 6)^2\) = 100

\((0)^2 + ( 4 + 6 )^2\) = 100

So, y = 4.

anyone can plug other values but these values won't work as we have even exponents .

The best answer is B.
GMAT Club Bot
What is the largest possible value of y if (x+3)^2 + (y+6)^2 = 100?   [#permalink] 22 Aug 2018, 01:20
Display posts from previous: Sort by

What is the largest possible value of y if (x+3)^2 + (y+6)^2 = 100?

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  





Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne