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overtherainbow
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what is the max triangle 23 Jun 2007, 14:43
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what is the max triangle?



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Himalayan
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what is the max triangle 23 Jun 2007, 15:00
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overtherainbow
what is the max triangle?
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the equilateral triangle gives the largest area so it is A.

area = =sqrt(3)/4
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overtherainbow
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what is the max triangle 23 Jun 2007, 15:33
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oa is B !
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Himalayan
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what is the max triangle 23 Jun 2007, 20:57
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Himalayan
overtherainbow
what is the max triangle?

the equilateral triangle gives the largest area so it is A.

area = =sqrt(3)/4
Show more


i got it. the the issoceles, not the equilateral, triangle gives the largest area. i was confused between the two triangles..

then it is B.
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shoonya
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what is the max triangle 23 Jun 2007, 21:56
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Himalayan
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overtherainbow
what is the max triangle?

the equilateral triangle gives the largest area so it is A.

area = =sqrt(3)/4

i got it. the the issoceles, not the equilateral, triangle gives the largest area. i was confused between the two triangles..

then it is B.
Show more


But, the triangle is an isosceles triangle (given). so, it has to be something else beside being an isosceles triangle that would maximise the area.
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GK_Gmat
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what is the max triangle 24 Jun 2007, 08:39
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Can someone please post the question for this? I cannot see it here. Thanks.
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what is the max triangle 24 Jun 2007, 10:32
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Himalayan
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[quote="Himalayan"][quote="overtherainbow"]what is the max triangle?

the equilateral triangle gives the largest area so it is A.

area = =sqrt(3)/4

i got it. the the issoceles, not the equilateral, triangle gives the largest area. i was confused between the two triangles..

then it is B.

But, the triangle is an isosceles triangle (given). so, it has to be something else beside being an isosceles triangle that would maximise the area.[/quote]

how? any example.[/quote]

Himalayan, the two sides of the given triangle are equal to the radius of the circle. Hence it's isosceles. We need some other information to maximise the area.

I solved it using calculus. But, I'm still looking for an easy method.



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Hi there,
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