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Updated on: 14 Nov 2013, 12:53
Originally posted by marcodonzelli on 15 Mar 2008, 11:52.
Last edited by Bunuel on 14 Nov 2013, 12:53, edited 1 time in total.
Last edited by Bunuel on 14 Nov 2013, 12:53, edited 1 time in total.
Added the OA.
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
30% (01:23) correct
70%
(01:15)
wrong
based on 609
sessions
History
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Time
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Not Attempted Yet
What is the maximum number of pieces that a circular pie can be divided into by four linear cuts?
A. 6
B. 8
C. 9
D. 10
E. 11
A. 6
B. 8
C. 9
D. 10
E. 11
25 Feb 2012, 03:59
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marcodonzelli
What is the maximum number of pieces that a circular pie can be divided into by four linear cuts?
A. 6
B. 8
C. 9
D. 10
E. 11
Can someone show this to me with a picture?
A. 6
B. 8
C. 9
D. 10
E. 11
Can someone show this to me with a picture?
Such kind of combinations problems are always about a pattern recognition.
Maximum pieces:
0 line gives 1 whole piece;
1 line will gives 2 pieces: 1+1=2;
2 lines will give 4 pieces: 2+2=4;
3 lines will give 7 pieces: 4+3=7;
4 lines will give 7+4=11 pieces.
Similarly:
5 lines will give 11+5=16 pieces;
6 lines will give 16+6=22 pieces;
7 lines will give 22+7=29 pieces.
So, generally kth line will add k new pieces.
Answer: E.
P.S. Though I agree, it doesn't seem to be GMAT type of question.
16 Mar 2008, 01:43
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1. 1st line can divide a circular pie by maximum 2 pieces
2. 2nd line gives us maximum 4 pieces
3. 3rd line can cross 3 pieces (to cross 4 piece is impossible) and we obtain 1+3*2=7 pieces
4. 4th line can cross maximum 4 pieces and we obtain 3+4*2=11
It can be solve less than 1min by means of the consecutive steps
2. 2nd line gives us maximum 4 pieces
3. 3rd line can cross 3 pieces (to cross 4 piece is impossible) and we obtain 1+3*2=7 pieces
4. 4th line can cross maximum 4 pieces and we obtain 3+4*2=11
It can be solve less than 1min by means of the consecutive steps
