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Bunuel
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If we assume the nos as (a-1), a, (a+1)
Combinig 1 & 2, we get : a+a-1+a+1 = a*(a-1)(a+1) =0
or, 3a = 0
hence only 1 solution : -1,0,+1
peeps88
I took three consecutive integers as - x-1, x, x+1.
1) cleary NS
2) Did - (x-1) + x + (x+1) = x(x-1)(x+1)
Got the values of X as -2,2 therefore NS

Combined 1 and 2 and just could not get the set with something that will have 0 in it cause
either it will be -3,-2,-1 OR 1,2,3.
Where did i go wrong here?
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