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MarmikUpadhyay
Bunuel
What is the median of the numbers 4, 5, 6, 7, 9, and x?

(1) x > 7
(2) The mean of the six numbers is equal to their median.

Median of 4, 5, 6, 7, 9 and x =?

Statement 1:
x > 7
If x > 7, then 6 and 7 are the two middle terms in ascending order.
Median = Average of 6 and 7 = 6.5
Statement 1 is Sufficient.

Statement 2:
Mean = Median
If x = 2, then Mean = Median = 5.5
If x = 8, then Mean = Median = 6.5
Statement 2 is Not Sufficient.

So, correct answer is option A.

Hi MarmikUpadhyay, Statement 2 states mean = median
We know that if mean = median, then the set has to be evenly spaced. How can we assume x to be 4?
Though your answer seems correct as you have rejected option B with two different options.
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Bunuel
What is the median of the numbers 4, 5, 6, 7, 9, and x?

(1) x > 7
(2) The mean of the six numbers is equal to their median.

Median of 4, 5, 6, 7, 9 and x =?

Statement 1:
x > 7
If x > 7, then 6 and 7 are the two middle terms in ascending order.
Median = Average of 6 and 7 = 6.5
Statement 1 is Sufficient.

Statement 2:
Mean = Median
If x = 2, then Mean = Median = 5.5
If x = 8, then Mean = Median = 6.5
Statement 2 is Not Sufficient.

So, correct answer is option A.

Hi MarmikUpadhyay, Statement 2 states mean = median
We know that if mean = median, then the set has to be evenly spaced. How can we assume x to be 4?
Though your answer seems correct as you have rejected option B with two different options.

Look if x < 5, Median = 5.5 and if Median > 7 Median = 6.5
For above two cases, Mean can be 5.5 for x = 2 and 6.5 for x = 8.
We can have one more case where 5 < x < 7, but it will be tedious and unnecessary as we got two different values of x, so no need for this case.
I hope it helps!

P.S. We didn't assume x to be anything, we can go in reverse manner like I showed above.
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What is the median of the numbers 4, 5, 6, 7, 9, and x?

Stat1: x > 7
x can be 8, 9.... still median will depend on 6 and 7. Sufficient

Stat2: The mean of the six numbers is equal to their median.
It means x can be on left side or right of mid number, so x can be 2 or 8. Then median will change, as sum will. Not sufficient

So, I think A. :)
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