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What is the median of the data set S that consists of the integers 17
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21 Sep 2019, 15:29
from statement (1), \(\frac{x+10+15+17+26+29}{6} = 17\) ---> we have one variable, so sufficient and \(x = 5\) and the median = \(\frac{15+17}{2} = 16\)
from statement (2), the current range without x is 19, so either \((29-x) = 24\) or \((x-10) = 24\) and x is either 5 or 34 respectively, and the median will be \(\frac{15+17}{2}\) or \(\frac{17+26}{2}\) respectively --> insufficient
What is the median of the data set S that consists of the integers 17
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Updated on: 17 May 2021, 07:37
Expert Reply
Top Contributor
gmatt1476 wrote:
What is the median of the data set S that consists of the integers 17, 29, 10, 26, 15, and x ?
(1) The average (arithmetic mean) of S is 17. (2) The range of S is 24.
Target question:What is the median of the data set S
Statement 1: The average (arithmetic mean) of S is 17. In other words, (17 + 29 + 10 + 26 + 15 + x)/6 = 17 At this point, we should recognize that we COULD solve this equation for x, which means we COULD answer the target question with certainty. Statement 1 is SUFFICIENT
Statement 2: The range of S is 24. When we arrange the five known numbers in ASCENDING ORDER, we get: 10, 15, 17, 26, 29 29 - 10 = 19, so the five KNOWN numbers have a range of 19. To get a range of 24, x can be less than 10 (the smallest of the five known numbers), OR x can be greater than 29 (the biggest of the five known numbers), That is, there are two possible values of x that will give us a range of 24: Case a: x = 5. In this case, the set becomes {5, 10, 15, 17, 26, 29}, which has a range of 24. Here, the answer to the target question is the median = (15 + 17)/2 = 16 Case b: x =34. In this case, the set becomes {10, 15, 17, 26, 29, 34}, which has a range of 24. Here, the answer to the target question is the median = (17 + 26)/2 = 21.5 Since we cannot answer the target question with certainty, statement 2 is NOT SUFFICIENT
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