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10 May 2022, 08:45
Kudos
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
85% (01:39) correct
15%
(01:49)
wrong
based on 33
sessions
History
Date
Time
Result
Not Attempted Yet
What is the nearest number to 12,199 which is exactly divisible by the product of the first four prime numbers?
(A) 12,180
(B) 12,170
(C) 11,280
(D) 11,270
(E) 11,210
(A) 12,180
(B) 12,170
(C) 11,280
(D) 11,270
(E) 11,210
10 May 2022, 09:14
Kudos
Bookmarks
Bunuel
First 4 prime numbers: 2, 3, 5 and 7.
Clearly all 4 must be factors of the given number.
From 5 options
1) We can see all of them contains 5 * 2 (=10) as factors
2) Add the digits of each number in given options to test their divisibility by 3. This eliminates B, D and E, and we are left with A and C.
3) Now divide 12,180 (A) by 7 [12180/7=1740]. We see it is divisible by 7. At this point we already have our answer.
4) To confirm divide 11280 (C) by 7 [11280/7=1611 Reminder 3]
A is our answer
