Last visit was: 27 Apr 2026, 15:11 It is currently 27 Apr 2026, 15:11
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
cat2010
Joined: 26 Nov 2022
Last visit: 18 Mar 2023
Posts: 106
Own Kudos:
163
 [2]
Given Kudos: 12
Location: India
GMAT 1: 700 Q46 V40
GPA: 3.8
GMAT 1: 700 Q46 V40
Posts: 106
Kudos: 163
 [2]
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
User avatar
poorvi125
Joined: 08 Jun 2022
Last visit: 04 Feb 2024
Posts: 39
Own Kudos:
Given Kudos: 592
Posts: 39
Kudos: 8
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
7Amulya
Joined: 28 Mar 2022
Last visit: 16 Apr 2026
Posts: 23
Own Kudos:
Given Kudos: 554
Posts: 23
Kudos: 2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
SaquibHGMATWhiz
User avatar
GMATWhiz Representative
Joined: 23 May 2022
Last visit: 12 Jun 2024
Posts: 623
Own Kudos:
Given Kudos: 6
Location: India
GMAT 1: 760 Q51 V40
Expert
Expert reply
GMAT 1: 760 Q51 V40
Posts: 623
Kudos: 779
Kudos
Add Kudos
Bookmarks
Bookmark this Post
cat2010
What is the perimeter of Rhombus ABCD ?

Statement 1: ΔABD has perimeter 15 .

Statement 2: ΔABC is equilateral.

Solution:
Pre Analysis:
  • We are asked the perimeter of rhombus ABCD
  • If we assume the length of sides of the rhombus be \(a\), then we need the value of \(4a\)
Attachment:
rhombus2.png
rhombus2.png [ 8.49 KiB | Viewed 1339 times ]

Statement 1: ΔABD has perimeter 15
  • Accoridig to this statement, \(a+a+BD=15\)
  • This will not help us get the value of \(a\) or \(4a\)
  • Thus, statement 1 alone is not sufficient and we can eliminate options A and D

Statement 2: ΔABC is equilateral
  • Accoriding to this statement, \(AC=AB=CB=a\)
  • however, we still do not have an exact value of \(a\) or \(4a\)
  • Thus, statement 2 alone is also not sufficient

Combining:
  • From statement 1, \(2a+BD=15\)
  • From statement 2, \(AC=a\)
  • If we draw the diagonals, which are perpendicular to each other in the case of the rhombus, intersecting at point O
  • we have \(CO=OA=\frac{AC}{2}=\frac{a}{2}\)
    Attachment:
    rhombus3.png
    rhombus3.png [ 12.99 KiB | Viewed 1314 times ]
  • We can use Pythagoras theorem in triangle BOC to get the value of BO
  • Double of BP will be BD
  • Which can then be used to get the value of a from \(2a+BD=15\)

Hence the right answer is Option A
Moderators:
Math Expert
109929 posts
498 posts
212 posts