Gladiator59 wrote:
Looks like it is a bit off
dave13. I got perimeter as \(4(1+\sqrt{3})\)
Please find my working in the image attached ( I was bored to type it all!
)
Let me know if it makes sense.
Best,
Gladi
dave13 wrote:
Okay second try
from both statements we know that we have right angle \(x\), \(2x\), \(x\sqrt{3}\) and its height is \(4\)
In other words \(x\sqrt{3}\) = \(4\sqrt{3}\)
divide both sides by \(\sqrt{3}\) and get \(x =4\)
so the shortest leg is 4
the hypotenuse is 8
and height \(4\sqrt{3}\)
so perimetre of of right triangle is 4+8+\(4\sqrt{3}\) = 12+\(4\sqrt{3}\)
perimetre of right triangle is 12+\(4\sqrt{3}\)
is it correct answer ?
Hi Gladi,
Gladiator59, I hope my additional questions wont make you angry
many thanks for taking time to write the detailed solution, but i still have questions:
1. if Altitude is from Q to PR then why you put 4 as the base
or may be you drew this triangle it upside down ?
2. I dont understand why x which is hypotenuse equals \(\frac{8}{\sqrt{3}}\) if triangle is in the ratio x, 2x, 3x
where \(x\) is shortest leg, \(2x\) is a hypotenuse, and \(x\sqrt{3}\) then X a hypotenuse is 2*4 =8 can you please explain. based on which rule you make such division?
3. Same question for y, why you write \(y=4/\sqrt{3}\) shouldnt y be equal \(4\sqrt{3}\) based on which rule you make such division?
4. All in all if triangle is 30 60 90 and shortest leg is 4 which an altitude. then logically \(x = 4\), \(2x = 8\) and \(x\sqrt{3} = 4\sqrt{3}\) this is how I think, why ?
what`s wrong with my reasoning?
hello
pushpitkc chetan2u maybe you can help ?
These are questions I have so far
have a great weekend