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15 Jan 2019, 01:15
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
78% (02:42) correct
22%
(02:38)
wrong
based on 263
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\(\frac{5}{9}, \ \frac{5}{12}, \ \frac{23}{48}, \ \frac{11}{24}, \ \frac{3}{7}\).
What is the positive difference between the largest and the smallest of the fractions below.
A. 1/12
B. 5/36
C. 1/4
D. 1/3
E. 7/18
What is the positive difference between the largest and the smallest of the fractions below.
A. 1/12
B. 5/36
C. 1/4
D. 1/3
E. 7/18
15 Jan 2019, 06:33
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Solution
Given:
- • Few fractions
To find:
- • The difference between the largest and the smallest of the given fractions
Approach and Working:
\(\frac{5}{9}, \frac{5}{12}, \frac{23}{48}, \frac{11}{24}, \frac{3}{7}\)
- • \(\frac{5}{9} > \frac{5}{12}\)
• \(\frac{23}{48} > \frac{11}{24} = \frac{22}{48}\)
\(\frac{5}{9} = \frac{25}{45} > \frac{23}{48} > \frac{22}{48} > \frac{3}{7} = \frac{21}{49} > \frac{5}{12} = \frac{20}{48}\)
Therefore, the answer is \(\frac{5}{9} – \frac{5}{12} = \frac{5 * 3}{9 * 12} = \frac{5}{36}\)
Hence, the correct answer is Option B
Answer: B
KanishkM
Joined: 09 Mar 2018
Last visit: 18 Dec 2021
Posts: 755
Given Kudos: 123
Location: India
Schools: DeGroote'21 Desautels '21 NUS '21
15 Jan 2019, 06:58
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Bunuel
Now lets see, so many fractions, we can approximate to know which one will be the greatest and which will be the smallest
\(\frac{5}{9}\) will be > 1/2
\(\frac{5}{12}\) will be 20/48
\(\ \frac{23}{48}\)
\(\ \frac{11}{24}\) will be 22/48
\(\ \frac{3}{7}\) will be 21/49
You may notice that only 5/9 is greater than 1/2 which means this is the largest term,rest all will be less than 0.50
Now we need to find the smallest term, so as you notice there are three values with base as 48, out of which 20/48 will be the smallest.
5/9 - 5/12 = (20 - 15)/ 36 = 5/36
Correct Answer B
