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28 Aug 2005, 15:14
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What is the probability of getting two cards belonging to two different suits when two cards are drawn at random from a pack of well shuffled cards comprising 52 cards?
a. 1/13
b. 13/17
c. 13/51
d. 26/51
e. 12/51
Can you explain this one?
Thanks, Yaron
a. 1/13
b. 13/17
c. 13/51
d. 26/51
e. 12/51
Can you explain this one?
Thanks, Yaron
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THERE IS LIKELY A BETTER DISCUSSION OF THIS EXACT QUESTION.
This discussion does not meet community quality standards. It has been retired.
If you would like to discuss this question please re-post it in the respective forum. Thank you!
To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.
28 Aug 2005, 17:09
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hmm..i cant seem to get it. here's my working
Prob of drawing one card of a suit = 13/52 = 1/4
Prob of drawing second card of one of the 3 OTHER suits = 13*3/51(51 since one card has already been drawn). = 13/17
So i get (1/4)*(13/17) = 13/68 which of course isnt in the answers. so where did i go wrong?
Prob of drawing one card of a suit = 13/52 = 1/4
Prob of drawing second card of one of the 3 OTHER suits = 13*3/51(51 since one card has already been drawn). = 13/17
So i get (1/4)*(13/17) = 13/68 which of course isnt in the answers. so where did i go wrong?
28 Aug 2005, 17:29
Kudos
Bookmarks
I think it is B:
what card we get first doesn't matter, what matters is the second one. If we count the probability of getting the second card different from the first card we get the answer:
as we already took one card the total number is 51, and we have 39 cards that are different from the one that was taken first. So, the probability of getting a card different from the first is 39/51, or 13/17
what card we get first doesn't matter, what matters is the second one. If we count the probability of getting the second card different from the first card we get the answer:
as we already took one card the total number is 51, and we have 39 cards that are different from the one that was taken first. So, the probability of getting a card different from the first is 39/51, or 13/17
