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Bunuel
What is the probability that a fair die rolled once will land on either 4 or 5?

A. 1/36
B. 1/3
C. 1/2
D. 2/3
E. 5/6

Prob of selecting 2 (4 or 5) out of 6 = 2/6 = 1/3 IMO B
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Bunuel
What is the probability that a fair die rolled once will land on either 4 or 5?

A. 1/36
B. 1/3
C. 1/2
D. 2/3
E. 5/6


getting 4; 1/6 and 5 is 1/6
its OR ; 1/6+1/6 ; 2/6 ; 1/3
IMO B
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Bunuel
What is the probability that a fair die rolled once will land on either 4 or 5?

A. 1/36
B. 1/3
C. 1/2
D. 2/3
E. 5/6

Probability of getting 4 = 1/6
Probability of getting 5 = 1/6

4 or 5 = 1/6 + 1/6 = 2/6 = 1/3

IMO Option B

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Bunuel
What is the probability that a fair die rolled once will land on either 4 or 5?

A. 1/36
B. 1/3
C. 1/2
D. 2/3
E. 5/6

P(4 or 5) = 1/6 + 1/6 = 2/6 = 1/3

Answer: B
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We need to find What is the probability that a fair die rolled once will land on either 4 or 5?

As we are rolling one dice => Number of cases = \(6^1\) = 6

P(Getting a 4 or a 5) = P(4) + P(5) = \(\frac{1}{6}\) + \(\frac{1}{6}\) = \(\frac{2}{6}\) = \(\frac{1}{3}\)

So, Answer will be B
Hope it helps!

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Watch the following video to MASTER Dice Rolling Probability Problems

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