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# What is the reciprocal of (AB)/(A + B)^2 ?

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Joined: 02 Sep 2009
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What is the reciprocal of (AB)/(A + B)^2 ?  [#permalink]

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27 Jun 2016, 03:48
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Difficulty:

25% (medium)

Question Stats:

67% (00:55) correct 33% (01:12) wrong based on 60 sessions

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What is the reciprocal of $$\frac{(AB)}{(A + B)^2}$$ ?

A. $$\frac{(AB)}{(A^2 + 2AB + B^2)}$$.

B. $$\frac{A}{B} + \frac{B}{A} + AB$$.

C. $$\frac{B}{A} + \frac{A}{B} + 2$$.

D. $$\frac{(A^2 + B^2)}{AB}$$.

E. $$\frac{A}{B} + 2AB$$.

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Re: What is the reciprocal of (AB)/(A + B)^2 ?  [#permalink]

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27 Jun 2016, 04:10
reciprocal = (A+B)^2/AB
= (A^2+B^2+2AB)/AB = B/A + A/B +2
C
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Re: What is the reciprocal of (AB)/(A + B)^2 ?  [#permalink]

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27 Jun 2016, 12:35
1
Bunuel wrote:
What is the reciprocal of $$\frac{(AB)}{(A + B)^2}$$ ?

A. $$\frac{(AB)}{(A^2 + 2AB + B^2)}$$.

B. $$\frac{A}{B} + \frac{B}{A} + AB$$.

C. $$\frac{B}{A} + \frac{A}{B} + 2$$.

D. $$\frac{(A^2 + B^2)}{AB}$$.

E. $$\frac{A}{B} + 2AB$$.

$$\frac{(AB)}{(A + B)^2}$$

Reciprocal will be -

$$\frac{(A + B)^2}{(AB)}$$ => $$\frac{A^2}{AB} + \frac{B^2}{AB} + \frac{2AB}{AB}$$ => $$\frac{A}{B} + \frac{B}{A} + 2$$

Hence correct answer will be (C)

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Re: What is the reciprocal of (AB)/(A + B)^2 ?  [#permalink]

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19 Apr 2019, 05:45
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Re: What is the reciprocal of (AB)/(A + B)^2 ?   [#permalink] 19 Apr 2019, 05:45
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# What is the reciprocal of (AB)/(A + B)^2 ?

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