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15 Nov 2021, 08:45
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C
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Difficulty:
5%
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Question Stats:
92% (00:45) correct
8%
(01:12)
wrong
based on 100
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What is the remainder when 1551*1553*1555*1557*1559 is divided by 10?
(A) 0
(B) 2
(C) 5
(D) 7
(E) 9
(A) 0
(B) 2
(C) 5
(D) 7
(E) 9
yashikaaggarwal
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15 Nov 2021, 08:48
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The unit digit of "1551*1553*1555*1557*1559" is the remainder when its product is divided by 10.
=> 1*3*5*7*9 = 5 as unit digit
(Because multiplying any odd number with 5 will give 5 as a unit digit)
5 will be the remainder.
Answer is C
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=> 1*3*5*7*9 = 5 as unit digit
(Because multiplying any odd number with 5 will give 5 as a unit digit)
5 will be the remainder.
Answer is C
Posted from my mobile device
15 Nov 2021, 08:53
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We can use the multiplicative rule here to solve.
The reminder when the entire expression is divided by 10 = Product of reminder of each term
Therefore
Remainder =
(1551/10)*(1553/10)*(1555/10)*(1557/10)*(1559/10)
= (1)*(3)*(5)*(7)*(9)
= 945
Therefore the remainder will be 5
IMO C
The reminder when the entire expression is divided by 10 = Product of reminder of each term
Therefore
Remainder =
(1551/10)*(1553/10)*(1555/10)*(1557/10)*(1559/10)
= (1)*(3)*(5)*(7)*(9)
= 945
Therefore the remainder will be 5
IMO C
