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10 Apr 2025, 00:14
Kudos
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Solved it in 14 seconds.
First you have to understand that the units digit of 43 would be the same as the units digit of 3.
Second, the cyclicity (the power of a number after which the units digit starts to repeat in a fixed pattern) of 3 is 4.
So dividing the power 86 by 4, you get 2 as the remainder.
So our number will have the same units digit as 3^2, which is 9.
Dividing by 5, you get 4 as the remainder.
Answer (E).
First you have to understand that the units digit of 43 would be the same as the units digit of 3.
Second, the cyclicity (the power of a number after which the units digit starts to repeat in a fixed pattern) of 3 is 4.
So dividing the power 86 by 4, you get 2 as the remainder.
So our number will have the same units digit as 3^2, which is 9.
Dividing by 5, you get 4 as the remainder.
Answer (E).
Alterego
