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15 Jan 2017, 09:15
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
80% (00:38) correct
20%
(00:52)
wrong
based on 178
sessions
History
Date
Time
Result
Not Attempted Yet
What is the remainder when the number 14^2*15^8 is divided by 5?
A. 0
B. 1
C. 2
D. 4
E. 5
A. 0
B. 1
C. 2
D. 4
E. 5
Updated on: 19 Jan 2017, 17:23
Originally posted by OptimusPrepJanielle on 15 Jan 2017, 13:45.
Last edited by OptimusPrepJanielle on 19 Jan 2017, 17:23, edited 1 time in total.
Last edited by OptimusPrepJanielle on 19 Jan 2017, 17:23, edited 1 time in total.
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Bunuel
What is the remainder when the number 14^2*15^8 is divided by 5?
A. 0
B. 1
C. 2
D. 4
E. 5
A. 0
B. 1
C. 2
D. 4
E. 5
Last digit of 14^2 = 6
Last digit of 15^8 = 5
Last digit of multiplication = 0
Hence the remainder when (14^2)*(15^8) is divided by 5 = 0
Other way:
14^2*15^8 = 14^2*3^8*5^8
Hence this will always be divisible by 5
Correct option: A
15 Jan 2017, 16:33
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This post is not written properly. Since parentheses are needed to illustrate the exact operations.
In the current way written (14^2*15^8) it means: 14^{2*15^{8}}
The OptimusPrepJanielle gave a solution for (14^2)*(15^8) and this is perfectly divided by 5, since 15 is divided perfectly by 3, hence the quotient is an integer and the remainder 0. Which requires 0 operations.
The author should clarify what the right notation is.
In the current way written (14^2*15^8) it means: 14^{2*15^{8}}
The OptimusPrepJanielle gave a solution for (14^2)*(15^8) and this is perfectly divided by 5, since 15 is divided perfectly by 3, hence the quotient is an integer and the remainder 0. Which requires 0 operations.
The author should clarify what the right notation is.
