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10 Jul 2019, 05:09
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
86% (01:03) correct
14%
(01:25)
wrong
based on 42
sessions
History
Date
Time
Result
Not Attempted Yet
What is the sixth term of the sequence \(90, –30, 10, − \frac{10}{3}\), . . . ?
(A) \(\frac{1}{3}\)
(B) 0
(C) − \(\frac{10}{27}\)
(D) –3
(E) − \(\frac{100}{3}\)
(A) \(\frac{1}{3}\)
(B) 0
(C) − \(\frac{10}{27}\)
(D) –3
(E) − \(\frac{100}{3}\)
Source: Nova GMAT
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10 Jul 2019, 05:13
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SajjadAhmad
\(t_n = \frac{- t_n-1}{3}\)
90, -30, 10, -10/3, 10/9, -10/27
Sixth term = -10/27
IMO C
10 Jul 2019, 07:18
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There is an infinite number of possible sequences that begin with those four values. The question tells us nothing about how to deduce later values in the sequence from earlier ones, so the answer to this question can be literally anything. Sure, the sequence might be defined by the rule a_n = 90 (-1/3)^(n-1). But it might just as easily be defined by the rule
a_n = (n-1)(n-2)(n-3)(n-4) + 90(-1/3)^(n-1)
or in an infinite number of other ways. So this question makes no sense and the GMAT will never ask you anything remotely similar to this. If the GMAT is going to ask you for a term in a sequence, the GMAT will give you a rule that lets you deduce that term without any possible ambiguity.
a_n = (n-1)(n-2)(n-3)(n-4) + 90(-1/3)^(n-1)
or in an infinite number of other ways. So this question makes no sense and the GMAT will never ask you anything remotely similar to this. If the GMAT is going to ask you for a term in a sequence, the GMAT will give you a rule that lets you deduce that term without any possible ambiguity.
This Question is Locked Due to Poor Quality
Hi there,
The question you've reached has been archived due to not meeting our community quality standards. No more replies are possible here.
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