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D
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Difficulty:
45%
(medium)
Question Stats:
67% (01:44) correct
33%
(02:07)
wrong
based on 129
sessions
History
Date
Time
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Not Attempted Yet
What is the sum of all consecutive multiples of 8 between 400 and 600, inclusive?
A. 8000
B. 10,400
C. 12,500
D. 13,000
E. 15,000
A. 8000
B. 10,400
C. 12,500
D. 13,000
E. 15,000
28 Jun 2022, 08:42
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Bunuel
400 + 408 + 416 + 424 + .... + 600 = ???
8*(50 + .... + 75) = ???
8*(50 + 50 +1 + 50 + 2 + ... 50 + 25) = ???
8*(50*26 + 1 + 2 + ... + 25)
8*(50*26 + 25*26/2) = ???
8*(50*26 + 25*13) = ???
8*13*(50*2 + 25) = ???
104*(125) = 13000
OR
400 + 408 + 416 + 424 + .... + 600 = ???
8*(50 + .... + 75) = ???
75 - 50 + 1 = 26 (total 26 multiples)
26/2 = 13
So, mid point of 13 and 14 is 13.5
50 + 13.5 - 1 = 62.5 (since 50 i.e. 400 is inclusive)
62.5*8 = 500
Now sum = 500*26 = 13000
Answer D.
28 Jun 2022, 11:22
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Summation of an arithmetic progression is given by the first term plus the last term times the number of terms divided by 2
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