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02 Dec 2019, 01:23
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Difficulty:
75%
(hard)
Question Stats:
63% (02:31) correct
37%
(02:39)
wrong
based on 438
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What is the sum of all the integers from 90 to 920 that end in 7?
A. 44,094
B. 42,081
C. 41,361
D. 40,147
E. 39,168
Are You Up For the Challenge: 700 Level Questions
A. 44,094
B. 42,081
C. 41,361
D. 40,147
E. 39,168
Are You Up For the Challenge: 700 Level Questions
02 Dec 2019, 01:41
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First Term :97
Since, the integers end in 7, the common difference would be 10.
Last Term: 917
Total Number of Terms : (n)
917=97+(n-1)10
Solving, n=83
Sum of all integers between 90 and 920: (83*(97+917))/2 = 42081
Option (b)
Since, the integers end in 7, the common difference would be 10.
Last Term: 917
Total Number of Terms : (n)
917=97+(n-1)10
Solving, n=83
Sum of all integers between 90 and 920: (83*(97+917))/2 = 42081
Option (b)
02 Dec 2019, 02:26
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1. Numbers ending in 7 are 97, 107,117,127, ..., 917. The sequence comes out to be an Arithmetic progression with the common difference(d) as 10.
2. Using the formula (a)n= a1 + (n-1)d , we can determine the number n which comes out to be 83. {917=97+ (n-1)10 }
3. 83 can be used to find the sum of AP. Sum= (83/3)* ( 97+917) = 42,081
Option B
2. Using the formula (a)n= a1 + (n-1)d , we can determine the number n which comes out to be 83. {917=97+ (n-1)10 }
3. 83 can be used to find the sum of AP. Sum= (83/3)* ( 97+917) = 42,081
Option B
