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# What is the sum of the remainders of 6 consecutive integers that are e

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Math Expert
Joined: 02 Sep 2009
Posts: 58401
What is the sum of the remainders of 6 consecutive integers that are e  [#permalink]

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25 Jun 2019, 03:04
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Difficulty:

5% (low)

Question Stats:

89% (01:02) correct 11% (01:09) wrong based on 35 sessions

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What is the sum of the remainders of 6 consecutive integers that are each divided by 6?

A. 0
B. 1
C. 10
D. 15
E. 16

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Director
Joined: 22 Nov 2018
Posts: 557
Location: India
GMAT 1: 640 Q45 V35
GMAT 2: 660 Q48 V33
Re: What is the sum of the remainders of 6 consecutive integers that are e  [#permalink]

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25 Jun 2019, 04:07
Bunuel wrote:
What is the sum of the remainders of 6 consecutive integers that are each divided by 6?

A. 0
B. 1
C. 10
D. 15
E. 16

Since they are consecutive numbers one number will always be divisible by 6 (r=0) and one will always have R=1,2,3,4,5. So sum of remainders = 5*6/2=15 IMO D
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Re: What is the sum of the remainders of 6 consecutive integers that are e  [#permalink]

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25 Jun 2019, 05:07
Bunuel wrote:
What is the sum of the remainders of 6 consecutive integers that are each divided by 6?

A. 0
B. 1
C. 10
D. 15
E. 16

Take 6 consecutive integers as {1, 2, 3, 4, 5, 6}

Remainder when each number is divided by 6 = {1, 2, 3, 4, 5, 0}

Sum of remainders = 1 + 2 + 3 + 4 + 5 = 15

IMO Option D

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Re: What is the sum of the remainders of 6 consecutive integers that are e  [#permalink]

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26 Jun 2019, 02:06
Bunuel wrote:
What is the sum of the remainders of 6 consecutive integers that are each divided by 6?

A. 0
B. 1
C. 10
D. 15
E. 16

integers; 1-6 ; sum of remainders; 1+2+3+4+5+0 ; 15
IMO D
Re: What is the sum of the remainders of 6 consecutive integers that are e   [#permalink] 26 Jun 2019, 02:06
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