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# What is the sum of the square of the first n positive

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Manager
Joined: 11 Jan 2005
Posts: 101
What is the sum of the square of the first n positive [#permalink]

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26 Jan 2005, 23:11
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What is the sum of the square of the first n positive integer if the sum of the square of the first n even positive integer is A

1. 3A/4
2. A/2
3. A/3
4. A/4
5. A/8
SVP
Joined: 03 Jan 2005
Posts: 2233

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26 Jan 2005, 23:17
A=2^2+4^2+6^2+...=2^2*1^2+2^2*2^2+2^2*3^2+...=2^2(1^2+2^2+3^2+...)=4S

S=A/4
VP
Joined: 25 Nov 2004
Posts: 1483

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27 Jan 2005, 00:07
praveen_rao7 wrote:
shouldn't the answer be > A?

Nope.............

suppose n = 4

sum of sq of first n +ve even integers(A)= 2^2+4^2+6^2+8^2=120
sumof sq of first n +ve integers (a) =1^2+2^2+3^4^2 = 30
A/a=120/30
a=A/4
Manager
Joined: 28 Jan 2005
Posts: 98

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31 Jan 2005, 04:57
Great explanation. Just need to get used to the symbols here which tend to make things a little more confusing. Once I re-wrote using normal notation it made much more sense.
31 Jan 2005, 04:57
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