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mandy
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What is the sum of three digits than can be formed using 04 Sep 2005, 09:10
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What is the sum of three digits than can be formed using 1; 2 ,3 no repetition of digits ?


plz explain your work

thanks



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What is the sum of three digits than can be formed using 04 Sep 2005, 18:04
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123+132+231+213+321+312=1332

don't see any shortcut here
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qpoo
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What is the sum of three digits than can be formed using 04 Sep 2005, 19:58
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well, how about this:

for the left most digit, if it takes on the value of 3, it will be 3x10^2,
but this can appear 2! times, since there are 2 other digits undecided.
So we get 2x3x10^2, similiarly for 1,2
the total will be 2x(3+2+1)x10^2

repeat the same for the other two digits, we get:
111x12 = 1332
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mandy
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What is the sum of three digits than can be formed using 05 Sep 2005, 10:15
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The total number that can be made in using 3 digits is 6!
2 of this number will have 1 in the units digit , 2 will have 1 in the tenths digit and 2 of this number will have 1 in the hundred digit
similarly 2 OF Such exist for the 2 and 3

however i don 't understand how they find this number of 2 as the number of time each digit appear

if 3 OCCURS at the unit place , then the remaing digit can happen in 2! ways

in the unit place the sum will be 2 (1+2+3)= 12UNIT

3 OCCURS aat the Tenth place , then the remaing digit can happen in 2! ways in the tenth place the sum will be 2 (1+2+3)= 12 tenth or 120

SAME for hundredths
so the 12 +120+1200 ADD UP TO 1332




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kog
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What is the sum of three digits than can be formed using 07 Sep 2005, 04:43
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each digit will be in each column twice. The sum of the digits are 12
so 1200 + 120 + 12 = 1332
12
120
1200

3!/3 = 2 or 6 total combinations and only 3 digits so each digit appears in each place twice.
so 3 + 2 + 1 = 6 and 6 * 2 = 12
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What is the sum of three digits than can be formed using 08 Sep 2005, 15:00
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kog
each digit will be in each column twice. The sum of the digits are 12
so 1200 + 120 + 12 = 1332
12
120
1200

3!/3 = 2 or 6 total combinations and only 3 digits so each digit appears in each place twice.
so 3 + 2 + 1 = 6 and 6 * 2 = 12
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Plz Kog how did you find each digit appear twice ?

thanks



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