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Bunuel
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Bunuel
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Soma2001
(20/100)/(40/100) = 1/4
Sqaure root of 1/4 = 1/2

I think you missed something there. No?
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Soma2001
(20/100)/(40/100) = 1/4
Sqaure root of 1/4 = 1/2

(20/100)/(40/100) = 1/4 - Wrong
It will be 1/2..
Sqrt(1/2) is the correct value but the answers are in %..

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Explanation

=√(20/40)%
=√(1/2)%
=1/√2

In % , 100/√2
= 50√2
IMO-D


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To me both c and d looks correct
The answer should be sqrt(1/2) but since we need to answer the question in terms of %

Option C & D, both results in sqrt(1/2)..Where I am going wrong ?

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Gauravji21
To me both c and d looks correct
The answer should be sqrt(1/2) but since we need to answer the question in terms of %

Option C & D, both results in sqrt(1/2)..Where I am going wrong ?

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C should have been \((\frac{50}{\sqrt{2}})\%\). Fixed. Thank you!
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Bunuel
What is the value of \(\sqrt{\frac{20\%}{40\%}}\)?


A. \((\frac{1}{2})\%\)

B. \((\frac{1}{\sqrt{2}})\%\)

C. \((\frac{50}{\sqrt{2}})\%\)

D. \((50\sqrt{2})\%\)

E. \((100\sqrt{2})\%\)


FRESH GMAT CLUB TETS' QUESTION

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Answer should be B

0.2/0.4 = 2/4 = 1/2

Hence answer should be √1/√2 which is 1/√2

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________ ___ ___ ______ _ _
√20%/40% = √1/2 = √0.5 = √0.25*2 = 0.5√2 = 50√2%
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