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Bunuel
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Bunuel
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One squared quantity minus another squared quantity is a signal that you should use the difference of squares identity:

\(a^2 - b^2 = (a + b)(a - b)\)

In this case, the original expression \(\sqrt{404^2 - 396^2} \) becomes:

\(\sqrt{(404 + 396)(404 - 396)}\)

Then simplify:

\(\sqrt{(800)(8)}\)

\(\sqrt{6400}\)

80

The answer is B.

Note that in some cases, it's also helpful to go the other direction in the difference of squares identity rather than add/subtract within the parentheses. For example:

(100 + 9)(100 - 9) ---> 10,000 - 81 ---> 9,919

Always look out for the difference of squares. The GMAT frequently likes to include this identity when it tests algebraic concepts.
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[ltr]\sqrt{404^2-396^2}

here we can use a^2- b^2 = (a-b)(a+b)

√(404−396)(404+396)
(8)(800)
6400

taking square root of it gives = 8*10= 80

choice B

[/ltr]


Bunuel
What is the value of \(\sqrt{404^2 - 396^2}\) ?

(A) 60

(B) 80

(C) 90

(D) 120

(E) 144

This is a PS Butler Question

Check the links to other Butler Projects:

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This exercise can be solved using the difference of squares: \((a^2-b^2)=(a+b)*(a-b)\)

\(\sqrt{404^2-396^2} = \) \(\sqrt{(404+396)*(404-396)} = \) \(\sqrt{800*8}\) \(= \sqrt{6400 }= 80\)

Answer: B
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