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19 Oct 2020, 06:18
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
90% (01:36) correct
10%
(02:24)
wrong
based on 100
sessions
History
Date
Time
Result
Not Attempted Yet
What is the value of ab if the sum of the squares of positive integers a and b is 80?
(A) 4
(B) 16
(C) 30
(D) 32
(E) 64
(A) 4
(B) 16
(C) 30
(D) 32
(E) 64
19 Oct 2020, 06:47
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Given that \(a^2 + b^2 = 80\) and that a and b are integers
The only pair (a,b) that satisfies the above is (4,8)
Therefore ab = 4*8 = 32
Option D
Arun Kumar
The only pair (a,b) that satisfies the above is (4,8)
Therefore ab = 4*8 = 32
Option D
Arun Kumar
19 Oct 2020, 10:07
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GMATBusters
The question obviously has at least two answers, one positive and one negative. 4 and 8 are the only two positive integers that work, but it's also possible, for example, that a = -4 and b = 8, because (-4)^2 + 8^2 = 80 as well. So ab can equal 32 or -32.
Unless the question says a and b are positive integers, it needs to ask what the value of ab "could be", not what the value "is", since there is more than one solution.
19 Oct 2020, 11:33
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GMATBusters
a^2 + b^2 = 80
value of both a and b < 9, 9^2 =81 >80
only square 8 and 4 shows 80, 8^2 + 4^2 = 80
so, ab = 4*8 = 32
answer D
