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18 Jun 2020, 21:56
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Difficulty:
45%
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Question Stats:
63% (01:03) correct
38%
(01:53)
wrong
based on 8
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What is the value of \(x\)?
(I)\( (-x)^2 = - (x)^2\)
(II) \((-x)^3 = - (x)^3\)
(I)\( (-x)^2 = - (x)^2\)
(II) \((-x)^3 = - (x)^3\)
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yashikaaggarwal
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18 Jun 2020, 22:11
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What is the value of ?
(I) (-X)^2 = -(X)^2
=> X^2 = -X^2
=> an integer square is only equal to its negative square value when its positive and negative values are equal.
=> Such as, X = -X
Which is only possible in case of zero.
So X = 0
(Sufficient)
(II) (-X)^3 = -(X)^3
=> -X^3 = -X^3
=>. |X| = |X|
=> There are many possible case here to determine value of X.
(Insufficient)
Answer is A
Posted from my mobile device
(I) (-X)^2 = -(X)^2
=> X^2 = -X^2
=> an integer square is only equal to its negative square value when its positive and negative values are equal.
=> Such as, X = -X
Which is only possible in case of zero.
So X = 0
(Sufficient)
(II) (-X)^3 = -(X)^3
=> -X^3 = -X^3
=>. |X| = |X|
=> There are many possible case here to determine value of X.
(Insufficient)
Answer is A
Posted from my mobile device
18 Jun 2020, 22:23
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yashikaaggarwal, I couldn't catch statement 2 yet.
=>. |X| = |X|
=> There are many possible case here to determine value of X.
(Insufficient)
Why does it get absolute value? Could you please explain statements two with related concepts?
=>. |X| = |X|
=> There are many possible case here to determine value of X.
(Insufficient)
Why does it get absolute value? Could you please explain statements two with related concepts?
