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What is the value of y ? (1) 6x + 10y = 42 (2) 5x − 3y = 1

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What is the value of y ? (1) 6x + 10y = 42 (2) 5x − 3y = 1  [#permalink]

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New post 04 Mar 2019, 23:51
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A
B
C
D
E

Difficulty:

  5% (low)

Question Stats:

93% (00:43) correct 7% (01:36) wrong based on 55 sessions

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Re: What is the value of y ? (1) 6x + 10y = 42 (2) 5x − 3y = 1  [#permalink]

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New post 05 Mar 2019, 00:35
What is the value of y ?
(1) 6x + 10y = 42
(2) 5x − 3y = 1
We have no information if 'y' is interger or not and also positive or negative.
So Solving (1) :
Assume x=1; then y=3.6
Assume x=2; then y=3. No specific value.
Also, there are two variables and one equation, we cannot solve.
Same is the issue with (2) statement.
(1)+(2) - Can be solved.
So Answer must be 'C'.
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Re: What is the value of y ? (1) 6x + 10y = 42 (2) 5x − 3y = 1  [#permalink]

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New post 05 Mar 2019, 08:56
Bunuel wrote:
What is the value of y ?

(1) 6x + 10y = 42
(2) 5x − 3y = 1


#1
6x+10y=42
3x+5y=21
x & y values cannot be determined; insufficient
#2
5x-3y=1
x & y values cannot be determined; insufficient
from 1 & 2
yes we can determine values of x& y
sufficient
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Re: What is the value of y ? (1) 6x + 10y = 42 (2) 5x − 3y = 1  [#permalink]

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New post 05 Jun 2019, 06:37
Bunuel wrote:
What is the value of y ?

(1) 6x + 10y = 42
(2) 5x − 3y = 1


For sums like this we must check the trap, if two equations are proportional (Like parallel lines) then they can't be solved.

E.g.
6x + 10y = 42 &
12x + 20y = 84

But here the given two equations are not the same so they are intersecting lines, we can find (x,y)

C: Take both statements together to solve.
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Re: What is the value of y ? (1) 6x + 10y = 42 (2) 5x − 3y = 1   [#permalink] 05 Jun 2019, 06:37
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