JJ2014 wrote:

what is the value of y?

(1) x^2 - y^2 = 5

(2) x and y are each positive integers

Hi,

From 1, we get (x-y)(x+y)=5 i.e (x-y)=1,5 or (x+y)= 5,1...solving we get 2 values of y (one positive and one negative)

From 2 alone we get nothing

combining 1 & 2 we get X and Y as postive and we get one solution

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