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25 Nov 2007, 19:39
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Please provide details. Thanks
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25 Nov 2007, 23:38
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C
1. or 2. it is obviously that 1 and 2 along are insufficient. For 1 statement we can move U along PT to change angle x
1&2. QRS and UTS are isosceles triangles
angle(QSR)= (180-angle(QRS))/2
angle(UST)= (180-angle(UTS))/2
x+angle(QSR)+angle(UST)=180 ==>
x=180- (180-angle(QRS))/2-(180-angle(UTS))/2=(angle(QRS)+angle(UTS))/2
but for right triangle: angle(QRS)+angle(UTS)=90
Therefore, x=90/2=45 sufficient
1. or 2. it is obviously that 1 and 2 along are insufficient. For 1 statement we can move U along PT to change angle x
1&2. QRS and UTS are isosceles triangles
angle(QSR)= (180-angle(QRS))/2
angle(UST)= (180-angle(UTS))/2
x+angle(QSR)+angle(UST)=180 ==>
x=180- (180-angle(QRS))/2-(180-angle(UTS))/2=(angle(QRS)+angle(UTS))/2
but for right triangle: angle(QRS)+angle(UTS)=90
Therefore, x=90/2=45 sufficient
26 Nov 2007, 00:23
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alimad
Wow thanks for posting this. After working on this for about 6minutes, i finally solved this problem. I had this on a previous GPrep and guessed C. I wasnt actually able to solve for X though this time around.
Please see drawing.
Ok we have angle X.
S1: for the smaller triangle we have z and y and y. z+2y=180* from here we cannot figure anything else out. Insuff.
S2: we have angle n, and 2 w's. Same as s1, though cannot figure anything else out.
Together we have x+y+w=180*
we also have 2y+z=180*
n+2w=180*.
No look at big triangle we have angles z, 90*, and n. so z+n+90*=180*
z+n=90*.
heres the trick to solve this: add
2y+z=180*
2w+n=180*
we have 2y+2w+z+n=360*---> plug in for z+n--> 2y+2w+90*=360*
y+w=135* No plug into x+y+w --> x= 45*
Answer is C.
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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