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73% (01:52) correct
27%
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When 2 numbers are selected from the integers from 1 to 21 inclusive, what is the probability that the 2 selected numbers are prime numbers?
A. \(\frac{2}{15}\)
B. \(\frac{1}{5}\)
C. \(\frac{1}{3}\)
D. \(\frac{4}{15}\)
E. \(\frac{2}{5}\)
A. \(\frac{2}{15}\)
B. \(\frac{1}{5}\)
C. \(\frac{1}{3}\)
D. \(\frac{4}{15}\)
E. \(\frac{2}{5}\)
31 Jul 2018, 01:00
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MathRevolution
[Math Revolution GMAT math practice question]
When \(2\) numbers are selected from the integers from \(1\) to \(21\) inclusive, what is the probability that the \(2\) selected numbers are prime numbers?
\(A. \frac{2}{15}\)
\(B. \frac{1}{5}\)
\(C. \frac{1}{3}\)
\(D. \frac{4}{15}\)
\(E. \frac{2}{5}\)
When \(2\) numbers are selected from the integers from \(1\) to \(21\) inclusive, what is the probability that the \(2\) selected numbers are prime numbers?
\(A. \frac{2}{15}\)
\(B. \frac{1}{5}\)
\(C. \frac{1}{3}\)
\(D. \frac{4}{15}\)
\(E. \frac{2}{5}\)
Prime numbers till 21 - 2, 3, 5, 7, 11, 13 17 19 so 8 of them..
Total ways to select 2 out of 21..=21*20
Probability=8*7/21*20=2/15
A
31 Jul 2018, 01:03
Kudos
Bookmarks
MathRevolution
[Math Revolution GMAT math practice question]
When \(2\) numbers are selected from the integers from \(1\) to \(21\) inclusive, what is the probability that the \(2\) selected numbers are prime numbers?
\(A. \frac{2}{15}\)
\(B. \frac{1}{5}\)
\(C. \frac{1}{3}\)
\(D. \frac{4}{15}\)
\(E. \frac{2}{5}\)
When \(2\) numbers are selected from the integers from \(1\) to \(21\) inclusive, what is the probability that the \(2\) selected numbers are prime numbers?
\(A. \frac{2}{15}\)
\(B. \frac{1}{5}\)
\(C. \frac{1}{3}\)
\(D. \frac{4}{15}\)
\(E. \frac{2}{5}\)
1 is not a prime number
prime numbers between 1 and 21(inclusive) = 2,3,5,7,11,13,17,19=8
2 out of 8 can be selected in 8c2 ways = 28
2 out of 21 can be selected in 21c2 ways =210
probability of selecting 2 primes = 28/210=2/15
