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When a ball is thrown directly upwards, it is at a height of h feet,..

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When a ball is thrown directly upwards, it is at a height of h feet,..  [#permalink]

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New post 21 Nov 2018, 05:04
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A
B
C
D
E

Difficulty:

  35% (medium)

Question Stats:

71% (01:39) correct 29% (01:59) wrong based on 96 sessions

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When a ball is thrown directly upwards, it is at a height of h feet, above the ground, after t seconds. If h = \(800 – (t - 5)^4\) feet, then at what height will the ball be, before 3 seconds to reach the maximum height?

    A. 81
    B. 175
    C. 719
    D. 784
    E. 799

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Re: When a ball is thrown directly upwards, it is at a height of h feet,..  [#permalink]

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New post 21 Nov 2018, 05:11
Height, \(h = 800 - (t-5)^4\)
Height will be maximum when t is 5 seconds.

Height, h before 3 seconds to maximum height is when t is 2 seconds.

\(h = 800 - (2-5)^4\)
\(h = 800 - (-3)^4\)
\(h = 800 - 81\)
\(h = 719\)

C is the answer.
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When a ball is thrown directly upwards, it is at a height of h feet,..  [#permalink]

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New post 23 Nov 2018, 07:19

Solution



Given:
    • \(h = 800 – (t - 5)^4\) feet, where h = height above the ground in feet

To find:
    • The value of “h” when the ball is 3 seconds before it reaches the maximum height

Approach and Working:
    • \(h = 800 – (t - 5)^4\)
      o The maximum value of h = 800, since, the minimum value of \((t - 5)^4 = 0\)
      o Thus, at t = 5 sec, the ball reaches the maximum height

    • The value of t, three seconds before this will be 5 – 3 = 2 seconds
      o Implies, \(h = 800 – (2 - 5)^4 = 800 – 81 = 719\) feet

Hence the correct answer is Option C.

Answer: C
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When a ball is thrown directly upwards, it is at a height of h feet,..   [#permalink] 23 Nov 2018, 07:19
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