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01 Mar 2017, 05:25
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92% (01:40) correct
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When a dentist surveyed her 250 patients, 82% reported that they had brushed their teeth that day, 64% reported that they had flossed that day, and 52% reported that they had done both that day. How many of the dentist’s patients reported that they had neither brushed nor flossed that day?
A. 15
B. 16
C. 18
D. 21
E. 24
A. 15
B. 16
C. 18
D. 21
E. 24
01 Mar 2017, 11:57
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Bunuel
When a dentist surveyed her 250 patients, 82% reported that they had brushed their teeth that day, 64% reported that they had flossed that day, and 52% reported that they had done both that day. How many of the dentist’s patients reported that they had neither brushed nor flossed that day?
A. 15
B. 16
C. 18
D. 21
E. 24
A. 15
B. 16
C. 18
D. 21
E. 24
Percentage of patients done both is -
82 + 64 - 52 = 94
Thus, only 6% of the patients did not brush/flossed...
So, \(\frac{6}{100}*250 = 15\) patients neither brushed nor flossed that day
Hence, answer must be (A) 15
01 Mar 2017, 23:14
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We can use a table to solve this overlapping set problem:
Brush No B Total
F 0.52 0.64
No F X
Total 0.82 250
Brush No B Total
F 0.52 0.12 0.64
No F 0.06
Total 0.82 0.18 250
1% of 250 = 2.5
\(2.5*6 = 15\)
Brush No B Total
F 0.52 0.64
No F X
Total 0.82 250
Brush No B Total
F 0.52 0.12 0.64
No F 0.06
Total 0.82 0.18 250
1% of 250 = 2.5
\(2.5*6 = 15\)
