Vyshak
2^a = (2^x)*(2^(1/x))
2^b = (2^x)/(2^(1/x))
(2^a)^2 = 2^2a = (2^2x)*(2^2/x)
(2^b)^2 = 2^2b = (2^2x)/(2^2/x)
((2^a)^2)/(2^b)^2) = (2^2/x) * (2^2/x) = 2^4/x
If x = 1 then Answer = 16
If x = 2 then Answer = 4
If x = 4 then Answer = 1
If x = 4/3 then Answer = 8
If x = 4/5 then Answer = 32
Thus we can have multiple answers for this question since value of x is not specified. Please correct the question or let me know if I have made a mistake.
hi,
you are absolutely correct in your observation..
looking at the equation and the OA,
the equation could have been:-
(2^a)^(a+b)/(2^b)^(a+b)..try out this Q ..
just a point, in these Q to save time,
take the power to the numerator and then substitute for a and b..example
2^a/2^b= 2^(a-b)= 2^(x + 1/x - x - (1/x))= 2^(2/x)...
you should do this when you see a and b have common terms with change of sign..
Ofcourse, the way you have done is also absolutely correct..