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18 Jul 2018, 00:31
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
77% (01:40) correct
23%
(02:04)
wrong
based on 115
sessions
History
Date
Time
Result
Not Attempted Yet
When it was found that 150 more tickets for the school play were sold than the seating capacity of the auditorium. It was decided to have two performances. if the total number of tickets sold was equal to the total number who attended and if the auditorium was 2/3 full for each of the two performances, what is the seating capacity of the auditorium?
(A) 100
(B) 200
(C) 225
(D) 300
(E) 450
(A) 100
(B) 200
(C) 225
(D) 300
(E) 450
18 Jul 2018, 00:45
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+1 for E.
Let,
N = Total Capacity of Auditorium
Therefore,
( 2/3 )*N + ( 2/3 )*N = 150 + N
N = 450
Hence, E.
Let,
N = Total Capacity of Auditorium
Therefore,
( 2/3 )*N + ( 2/3 )*N = 150 + N
N = 450
Hence, E.
18 Jul 2018, 02:15
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Bunuel
Let the capacity of the auditorium be x.
Total tickets sold considering more than capacity = x+150
Now they decide to have 2 shows of equal no. of participants. So,
(x+150) /2
Now , we know that 2/3 of the capacity of the auditorium was full. We can form an equation :
(x+150) /2 = (2/3)x
x +150 = 4x / 3
3x +450 = 4x
x = 450. ( we assume x is the capacity )
The best answer is E.
