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When line k, expressed by the equation y = mx + b, is graphed on a [#permalink]
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28 Aug 2017, 23:57
Question Stats:
56% (00:44) correct 44% (00:35) wrong based on 75 sessions
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When line k, expressed by the equation y = mx + b, is graphed on a coordinate axis, does k intersect the origin? (1) m = 0 (2) b > 0 A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient. B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient. C. Both statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient. D. EACH statement ALONE is sufficient. E. Statements (1) and (2) TOGETHER are NOT SUFFICIENT.
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Re: When line k, expressed by the equation y = mx + b, is graphed on a [#permalink]
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29 Aug 2017, 01:11
Answer is B. If y intersect (i.e. b) >0, the line k (a straight line) will NOT intersect the origin. Enough.
Statement 1 is not sufficient. If b=0, line intersects. If not, line doesn't intersect.



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Re: When line k, expressed by the equation y = mx + b, is graphed on a [#permalink]
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29 Aug 2017, 01:29
1: m=0 It tells that slope of line is zero, i.e., it is a horizontal line. So it can or cannot pass through origin. Hence 1 is not sufficient.
2: b>0 So it is clear that intercept of this line is positive. So line cannot pass through origin. Hence it is sufficient to answer the question.



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Re: When line k, expressed by the equation y = mx + b, is graphed on a [#permalink]
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12 Oct 2017, 19:23
shivam2506 wrote: 1: m=0 It tells that slope of line is zero, i.e., it is a horizontal line. So it can or cannot pass through origin. Hence 1 is not sufficient.
2: b>0 So it is clear that intercept of this line is positive. So line cannot pass through origin. Hence it is sufficient to answer the question. If slope of line is zero, i.e., it is a horizontal line. then it will never pass through the origin right? Could u pls explain statement 1 again pls..



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Re: When line k, expressed by the equation y = mx + b, is graphed on a [#permalink]
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18 Oct 2017, 19:53
antztheman wrote: Answer is B. If y intersect (i.e. b) >0, the line k (a straight line) will NOT intersect the origin. Enough.
Statement 1 is not sufficient. If b=0, line intersects. If not, line doesn't intersect. How can u say line k is a straight line? Pls explain thank u



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Re: When line k, expressed by the equation y = mx + b, is graphed on a [#permalink]
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21 Oct 2017, 23:40
zanaik89 wrote: shivam2506 wrote: 1: m=0 It tells that slope of line is zero, i.e., it is a horizontal line. So it can or cannot pass through origin. Hence 1 is not sufficient.
2: b>0 So it is clear that intercept of this line is positive. So line cannot pass through origin. Hence it is sufficient to answer the question. If slope of line is zero, i.e., it is a horizontal line. then it will never pass through the origin right? Could u pls explain statement 1 again pls.. "If slope of line is zero, i.e., it is a horizontal line. then it will never pass through the origin right?" Since the slope of the line is zero so it is a horizontal line. But if this horizontal line has some value associated with abscissa, i.e., yaxis for example if y=2 or y=5 then this horizontal line will never pass through origin as it coordinate will be (0,2) or (0, 5), but if its abscissa, i.e., yaxis is 0, then the coordinates of this line will become (0,0) and hence it can pass thru origin. So from first statement we cannot give a sure answer. That's why it is ruled out.



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Re: When line k, expressed by the equation y = mx + b, is graphed on a [#permalink]
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28 Oct 2017, 13:36
DEATH wrote: When line k, expressed by the equation y = mx + b, is graphed on a coordinate axis, does k intersect the origin?
(1) m = 0
(2) b > 0
A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient. C. Both statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient. D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT SUFFICIENT. Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and independent equations ensures a solution. The first step of VA(Variable Approach) method is modifying the original condition and the question, and rechecking the number of variables and the number of equations. We can modify the original condition and question as follows. The property a line intersects the origin means that yintercept is 0. From the equation y = mx + b, yintercept is b and the question asks if b = 0. Thus the condition 2) only is sufficient. Therefore, B is the answer.
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Re: When line k, expressed by the equation y = mx + b, is graphed on a
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