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When line k, expressed by the equation y = mx + b, is graphed on a

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When line k, expressed by the equation y = mx + b, is graphed on a [#permalink]

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New post 28 Aug 2017, 23:57
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Question Stats:

50% (00:55) correct 50% (00:45) wrong based on 44 sessions

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When line k, expressed by the equation y = mx + b, is graphed on a coordinate axis, does k intersect the origin?

(1) m = 0

(2) b > 0

A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.

C. Both statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

D. EACH statement ALONE is sufficient.

E. Statements (1) and (2) TOGETHER are NOT SUFFICIENT.
[Reveal] Spoiler: OA

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Re: When line k, expressed by the equation y = mx + b, is graphed on a [#permalink]

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New post 29 Aug 2017, 01:11
Answer is B. If y intersect (i.e. b) >0, the line k (a straight line) will NOT intersect the origin. Enough.

Statement 1 is not sufficient. If b=0, line intersects. If not, line doesn't intersect.

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Re: When line k, expressed by the equation y = mx + b, is graphed on a [#permalink]

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New post 29 Aug 2017, 01:29
1: m=0 It tells that slope of line is zero, i.e., it is a horizontal line. So it can or cannot pass through origin. Hence 1 is not sufficient.

2: b>0 So it is clear that intercept of this line is positive. So line cannot pass through origin. Hence it is sufficient to answer the question.

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Re: When line k, expressed by the equation y = mx + b, is graphed on a [#permalink]

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New post 12 Oct 2017, 19:23
shivam2506 wrote:
1: m=0 It tells that slope of line is zero, i.e., it is a horizontal line. So it can or cannot pass through origin. Hence 1 is not sufficient.

2: b>0 So it is clear that intercept of this line is positive. So line cannot pass through origin. Hence it is sufficient to answer the question.


If slope of line is zero, i.e., it is a horizontal line. then it will never pass through the origin right?

Could u pls explain statement 1 again pls..

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Re: When line k, expressed by the equation y = mx + b, is graphed on a [#permalink]

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New post 18 Oct 2017, 19:53
antztheman wrote:
Answer is B. If y intersect (i.e. b) >0, the line k (a straight line) will NOT intersect the origin. Enough.

Statement 1 is not sufficient. If b=0, line intersects. If not, line doesn't intersect.


How can u say line k is a straight line?

Pls explain thank u

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Re: When line k, expressed by the equation y = mx + b, is graphed on a   [#permalink] 18 Oct 2017, 19:53
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