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When positive integer x is divided by 44, the remainder is 28
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30 Mar 2017, 08:35
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When positive integer x is divided by 44, the remainder is 28. When positive integer y is divided by 22, the remainder is 14. If N = x+y, what is the remainder when N is divided by 11? A) 1 B) 3 C) 5 D) 7 E) 9 *kudos for all correct solutions
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Re: When positive integer x is divided by 44, the remainder is 28
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30 Mar 2017, 08:51
GMATPrepNow wrote: When positive integer x is divided by 44, the remainder is 28. When positive integer y is divided by 22, the remainder is 14. If N = x+y, what is the remainder when N is divided by 11?
A) 1 B) 3 C) 5 D) 7 E) 9
*kudos for all correct solutions Good Question Brent.. When x is divided by 44, remainder is 28... So the number x is 44t+28, where t is integer..
When y is divided by 22, remainder is 14.. So the number y is 22s+14, where s is integer..
N=x+y = 44t+28+22s+14 So when N is divided by 11, \(\frac{44t+22s+42}{11}\) 44t and 22s are div by 11.. 42=11*3+9.. So 9 is the remainder E
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Re: When positive integer x is divided by 44, the remainder is 28
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30 Mar 2017, 10:46
GMATPrepNow wrote: When positive integer x is divided by 44, the remainder is 28. When positive integer y is divided by 22, the remainder is 14. If N = x+y, what is the remainder when N is divided by 11?
A) 1 B) 3 C) 5 D) 7 E) 9
*kudos for all correct solutions x = 44a+28( a = any integer) Let a =1 then x = 44+28= 72 similarly y=22b+14 (b=any integer) let b=1 then y= 36 thus N=x+y =72+36=108 108/11 = 9 9/11 thus 9is correct answer ans E



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Re: When positive integer x is divided by 44, the remainder is 28
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30 Mar 2017, 11:46
GMATPrepNow wrote: When positive integer x is divided by 44, the remainder is 28. When positive integer y is divided by 22, the remainder is 14. If N = x+y, what is the remainder when N is divided by 11?
A) 1 B) 3 C) 5 D) 7 E) 9
*kudos for all correct solutions x=44a+28;y=14+22b For a=1 and b=1 x=72,y=36 n=x+5=108 remainder9
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Re: When positive integer x is divided by 44, the remainder is 28
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30 Mar 2017, 11:54
GMATPrepNow wrote: When positive integer x is divided by 44, the remainder is 28. When positive integer y is divided by 22, the remainder is 14. If N = x+y, what is the remainder when N is divided by 11?
A) 1 B) 3 C) 5 D) 7 E) 9
*kudos for all correct solutions least values of x and y are 28 and 14 respectively x+y=42=N N/11 gives a remainder of 9 E



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Re: When positive integer x is divided by 44, the remainder is 28
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30 Mar 2017, 13:09
remainder 28 when divided by 44
so 44a + 28
remainder 14 when divided by 22
so 22b + 14
now N = x+y
44a + 22b + 42
N/11
as we know 44 and 22 are divisible by 11 only 42 is remaining
42/11 remainder = 2 or 9
44 2 = 42 33+9 = 42
E



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Re: When positive integer x is divided by 44, the remainder is 28
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04 Aug 2017, 09:45
HI! Did it by number picking Possible value of x = 28, 72, 100... Possible values of y = 14, 36, 58.... Since there can be only one unique solution, add to find the smallest possible value of n = 28 + 14 = 42. Remainder of 42/11 = 9 Correct answer: E Is the Kudos for correct solution still valid?
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Re: When positive integer x is divided by 44, the remainder is 28
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20 Jan 2019, 09:14
GMATPrepNow wrote: When positive integer x is divided by 44, the remainder is 28. When positive integer y is divided by 22, the remainder is 14. If N = x+y, what is the remainder when N is divided by 11?
A) 1 B) 3 C) 5 D) 7 E) 9
*kudos for all correct solutions Let \(x = 28\) and \(y = 14\) So, \(N = 28 + 14\) => \(42\) \(\frac{N}{11} = 11*3 + 9\), Thus Answer must be (E) 9
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Re: When positive integer x is divided by 44, the remainder is 28
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20 Jan 2019, 09:14






