Question stems provide with following information:
Assuming that there \(x\) people in group A then,
\(x = 13m + 0\) (No one is left over and m subgroups are formed of 13 people.)
Assuming that there \(y\) people in group B then,
\(y = 11n + 8\) (8 people left over and n subgroups are formed of 11 people.)
We need to find \(y\).
Statement-1We are given that m=n,
But that doesn't narrow down the possible number of total members of group B
Ex.
\(m = n = 1\)
\(x = 13, y = 19 \)
\(m = n = 2 \)
\(x = 26, y = 30 \)
Not sufficient.Statement-2\(x = y\)
\(13m = 11n + 8\)
Multiple values of m and n are possible that satisfy this equation.
\(m = 4, n = 4\)
\(m = 15, n = 17\)
Not sufficientCombining statement-1 and statement-2,\(13m = 11n + 8\)
and using \(m = n\),
\(13n = 11n + 8\)
\(n = 4\)
\(y = 11*4 + 8 = 52\)
Only 1 value of y is possible.
SufficientSo answer should be
C