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15 Feb 2007, 04:28
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When the positive integer x is divided by 11, the quotient is y and the remainder 3. When x is divided by 19, the remainder is also three. What is the remainder when y is divided by 19?
A. 0
B. 1
C. 2
D. 3
E. 4
A. 0
B. 1
C. 2
D. 3
E. 4
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15 Feb 2007, 04:33
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I pick A.
x/11=y+3
x/19=q+3
x=11y+3
x=19q+3
Substract one equation from the other.
11y-19q=0
11y=19q
Clearly from this we can see that y must have a factor of 19.... so the remainder will be 0.
x/11=y+3
x/19=q+3
x=11y+3
x=19q+3
Substract one equation from the other.
11y-19q=0
11y=19q
Clearly from this we can see that y must have a factor of 19.... so the remainder will be 0.
15 Feb 2007, 05:04
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Bookmarks
When the positive integer x is divided by 11, the quotient is y and the remainder 3. When x is divided by 19, the remainder is also three. What is the remainder when y is divided by 19?
A. 0
B. 1
C. 2
D. 3
E. 4
x = 11y+3
x = 19k+3
19k+3 = 11y+3
19k/11 = y
thus y is muktiple of 19 and remainder = 0
A IS MY ANSWER TOO
A. 0
B. 1
C. 2
D. 3
E. 4
x = 11y+3
x = 19k+3
19k+3 = 11y+3
19k/11 = y
thus y is muktiple of 19 and remainder = 0
A IS MY ANSWER TOO
