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Where am I making the mistake in below question?

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GGMAT760
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Where am I making the mistake in below question? [#permalink] New post   21 May 2014, 21:23
Simplify 4.5−2∗3/6+1/4^2 divided by 0.75

45/10- 1+1/16 divided by 3/4
9/2 - 17/16 dividend by 3/4
72-17/16 divided by 3/4
55/16 *4/3

But in the GMAT club test answer it comes 57/16 * 4/3

In that subtraction is done before addition. But I did addition before subtraction.
Can anyone please clarify PEMDAS rule for me? I understand multiplication and division comes before + and - but does not understand rule between + and - with out parenthes, * and division with out parenthes.

Thanks in advance..



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Re: Where am I making the mistake in below question? [#permalink] New post   21 May 2014, 21:32
drkomal2000 wrote:
Simplify 4.5−2∗3/6+1/4^2 divided by 0.75

45/10- 1+1/16 divided by 3/4
9/2 - 17/16 dividend by 3/4
72-17/16 divided by 3/4
55/16 *4/3

But in the GMAT club test answer it comes 57/16 * 4/3

In that subtraction is done before addition. But I did addition before subtraction.
Can anyone please clarify PEMDAS rule for me? I understand multiplication and division comes before + and - but does not understand rule between + and - with out parenthes, * and division with out parenthes.

Thanks in advance..


9/2 -1 +1/16 -----> (9/2 -15/16)/3/4 or 57/16*4/3

Your understanding is correct. But you made a silly mistake

Hope it helps
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Re: Where am I making the mistake in below question? [#permalink] New post   Updated on: 22 May 2014, 00:47
Just to break down Wounded Tiger's reply one step further:

\(-1+\frac{1}{16}\) = \(\frac{(-16+1)}{16}\) =\(\frac{-15}{16}\)

Here are two more similar practice problems for you:

1. What is the value of n =\(-\sqrt{\frac{9}{100}} + \frac{1}{3}/\frac{1}{6}+ 4 - \frac{1}{5}\)?

2. Find the value of n = \([6*-4/8+\frac{9}{-3}]/[20/-4+2]\).

Hope I could help!

Originally posted by JapinderKaur on 22 May 2014, 00:38.
Last edited by JapinderKaur on 22 May 2014, 00:47, edited 1 time in total.
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Re: Where am I making the mistake in below question? [#permalink] New post   22 May 2014, 00:46
SOLUTIONS

1. n = \(-\frac{3}{10} + \frac{1}{3}*6 + 4 - \frac{1}{5}\)
=\(-\frac{3}{10}+2+4-\frac{1}{5}\)
=\(6-\frac{5}{10}\)
=\(6- \frac{1}{2}\)
=\(\frac{11}{2}\)

2. n= \([6*\frac{-4}{8} + (-3)]/[\frac{20}{-4} + 2]\)
=\(\frac{(-3-3)}{(-5+2)}\)
= \(\frac{-6}{-3}\)
=2
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Re: Where am I making the mistake in below question? [#permalink] New post   22 May 2014, 02:34
One more similar question for practice:

\(\frac{1}{7} * [( 4 - \frac{18}{27} ) div by \frac{8}{3} + \frac{3}{8}* (\frac{7}{4} * \frac{7}{9} + \frac{5}{12}) ]\)


Answer: \(\frac{23}{84}\)



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Re: Where am I making the mistake in below question? [#permalink]
22 May 2014, 02:34
Moderator:
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