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57% (01:19) correct 43% (01:05) wrong based on 242 sessionsAs we have |x| in the equation so we will have two cases | |
-Case 1: x ≥ 0 => |x| = x => x - |x| = x - x = 0 => A is POSSIBLE If x = 0 then x-|x| = 0 = x => E is POSSIBLE | -Case 2: x < 0 => |x| = -x => x - |x| = x - (-x) = x + x = 2x => B is POSSIBLE If x = -1 => x - |x| = 2x = -2 < -1 => D is POSSIBLE |
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