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Updated on: 23 Sep 2018, 03:13
Originally posted by bettatantalo on 22 Sep 2018, 07:11.
Last edited by Bunuel on 23 Sep 2018, 03:13, edited 1 time in total.
Last edited by Bunuel on 23 Sep 2018, 03:13, edited 1 time in total.
Edited the question.
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E
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Difficulty:
15%
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Question Stats:
87% (01:07) correct
13%
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wrong
based on 57
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Which of the following does the expression \(\frac{3^b + 3^{b-1}}{3^{b+1}-3^b}\) equal.
a) 3
b) 4/3
c) 3/2
d) 3/4
e) 2/3
source gmat tutor
a) 3
b) 4/3
c) 3/2
d) 3/4
e) 2/3
source gmat tutor
22 Sep 2018, 09:31
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bettatantalo
One approach is to assign a nice/easy value to b and evaluate the expression.
How about b = 1
We get: (3^1 + 3^0)/(3^2 - 3^1)
Evaluate each power to get: (3 + 1)/(9 - 3)
Evaluate again: 4/6
Simplify: 1/3
Answer: E
Cheers,
Brent
22 Sep 2018, 17:39
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bettatantalo
GMATPrepNow , I think you meant \(\frac{2}{3}\).
The approach above is my preference.
Algebraically:
\(\frac{3^{b}+3^{b-1}}{3^{b+1}-3^{b}}=\)
\(\frac{3^{b}(1+3^{-1})}{3^{b}(3^1-1)}=\)
\(\frac{1+3^{-1}}{2}=\frac{1+\frac{1}{3}}{2}=\)
\(\frac{(\frac{4}{3})}{2}=(\frac{4}{3}*\frac{1}{2})=\frac{4}{6}=\frac{2}{3}\)
Answer E
bettatantalo , the other day a boorish poster treated you rudely. I commend you for trying to format properly. Try this trick: for formats you want to learn, "peek" at the formatting. Let's say you want to learn how to write compound fractions as I have in the final "math" line of this post. 1) get a picture of the "polished" format by screenshotting my post; then 2) get a peek at the formatting. Hit "reply" on my post. You will see the coded formatting. Take another screenshot. Then choose "cancel" or close the tab (your fake reply will not post). And ignore incivilty.
