GMAT Question of the Day - Daily to your Mailbox; hard ones only

It is currently 22 Feb 2019, 07:00

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
Events & Promotions in February
PrevNext
SuMoTuWeThFrSa
272829303112
3456789
10111213141516
17181920212223
242526272812
Open Detailed Calendar
  • Free GMAT RC Webinar

     February 23, 2019

     February 23, 2019

     07:00 AM PST

     09:00 AM PST

    Learn reading strategies that can help even non-voracious reader to master GMAT RC. Saturday, February 23rd at 7 AM PT
  • FREE Quant Workshop by e-GMAT!

     February 24, 2019

     February 24, 2019

     07:00 AM PST

     09:00 AM PST

    Get personalized insights on how to achieve your Target Quant Score.

Which of the following equations defines a line for which no points on

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:

Hide Tags

 
Current Student
User avatar
P
Status: Chasing my MBB Dream!
Joined: 29 Aug 2012
Posts: 1118
Location: United States (DC)
WE: General Management (Aerospace and Defense)
GMAT ToolKit User Premium Member Reviews Badge
Which of the following equations defines a line for which no points on  [#permalink]

Show Tags

New post 13 Nov 2017, 12:57
Top Contributor
4
00:00
A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

75% (01:25) correct 25% (01:27) wrong based on 116 sessions

HideShow timer Statistics

Which of the following equations defines a line for which no points on the line lie in quadrant III?

A.\(y = –3x + 4\)

B.\(y = 3x + 4\)

C.\(y= \frac{X}{3}+4\)

D.\(y = –3x – 4\)

E. \(y = 3x – 4\)

_________________

Become a GMAT Club Premium member to avail lot of discounts

SVP
SVP
User avatar
D
Joined: 26 Mar 2013
Posts: 2068
Reviews Badge CAT Tests
Which of the following equations defines a line for which no points on  [#permalink]

Show Tags

New post 13 Nov 2017, 15:02
1
Gnpth wrote:
Which of the following equations defines a line for which no points on the line lie in quadrant III?

A.\(y = –3x + 4\)

B.\(y = 3x + 4\)

C.\(y= \frac{X}{3}+4\)

D.\(y = –3x – 4\)

E. \(y = 3x – 4\)



The question simply asks line that does not have either x or y with NEGATIVE sign


A.\(y = –3x + 4\).......If x is negative then y is always positive............Keep....There is no points on the line lie in quadrant III.

B.\(y = 3x + 4\)........x = -2, then y = -2.........................................Eliminate

C.\(y= \frac{X}{3}+4\)........x = -36, then y = - 9.......... .Eliminate

D.\(y = –3x – 4\)................................x = -1 , then y = -1.............Eliminate

E. \(y = 3x – 4\).................................x = -1 , then y = -7.............Eliminate

Answer: A
Senior SC Moderator
avatar
V
Joined: 22 May 2016
Posts: 2491
Which of the following equations defines a line for which no points on  [#permalink]

Show Tags

New post 13 Nov 2017, 17:05
3
1
Gnpth wrote:
Which of the following equations defines a line for which no points on the line lie in quadrant III?

A.\(y = –3x + 4\)

B.\(y = 3x + 4\)

C.\(y= \frac{X}{3}+4\)

D.\(y = –3x – 4\)

E. \(y = 3x – 4\)


Conventional: find the intercepts and graph the line
Attachment:
lines.png
lines.png [ 4.11 KiB | Viewed 2154 times ]

Set x equal to zero, then y equal to zero to find x- and y-intercepts.
These equations are in point slope form, and the numbers aren't bad.

A. \(y = –3x + 4\)
\(x = 0: y = 4\)
\(y = 0: 3x = 4, x = \frac{4}{3}\)
POINTS \((0,4) , (\frac{4}{3}, 0)\)

B. \(y = 3x + 4\)
\(x = 0: y = 4\)
\(y = 0: -3x = 4, x = -\frac{3}{4}\)
POINTS \((0, 4) and (-\frac{3}{4}, 0)\)

C. \(y= \frac{X}{3}+4\)
\(x = 0: y = 4\)
\(y = 0: \frac{x}{3} = -4, x = -12\)
POINTS \((0, 4) and (-12, 0)\)

D. \(y = –3x – 4\)
\(x = 0: y = -4\)
\(y = 0: 3x = -4, x = -\frac{4}{3}\)
POINTS (\(0, -4) and ( -\frac{4}{3}, 0)\)

E. \(y = 3x – 4\)
\(x = 0: y = -4\)
\(y = 0: 3x = 4, x = \frac{4}{3}\)
POINTS \((0, -4) and (\frac{4}{3}, 0)\)

See diagram. Only A avoids Q III.

ANSWER A

Sketch generally: watch slope and y-intercept
This way is a lot faster: Figure out whether the line's slope and y-intercept should be positive or negative.

Sketch the two absolute cases: a line with a positive slope through the origin, and one with a negative slope through the origin. Go from there.
Attachment:
lines2.png
lines2.png [ 16.48 KiB | Viewed 2151 times ]

1. Sketch a line with a positive slope that passes through the origin: lines with positive slopes always pass through Quadrants I and III
Reject this one. We need to avoid Quadrant III. We need a negative slope

2) Sketch a line with a negative slope that passes through the origin
Lines with negative slopes always pass through Quadrants II and IV. How to avoid Q III?

3) Shift the line with the negative slope from the origin so that it does not pass through Q III
Note the y-intercept: it is positive

4) We need: a line with NEGATIVE slope and POSITIVE y-intercept

Check the options: Answers, B, C, and E are eliminated. Their slopes are positive

A. \(y = –3x + 4\)
Slope is -3
y-intercept is 4 (if x = 0, y = 4) KEEP

D. \(y = –3x – 4\)
Slope is -3
y-intercept is -4 (if x = 0, y = -4) REJECT

ANSWER A
_________________

To live is the rarest thing in the world.
Most people just exist.

Oscar Wilde

Senior Manager
Senior Manager
avatar
P
Joined: 17 Mar 2014
Posts: 439
GMAT ToolKit User Premium Member Reviews Badge CAT Tests
Re: Which of the following equations defines a line for which no points on  [#permalink]

Show Tags

New post 02 Feb 2019, 20:48
1
generis wrote:
Gnpth wrote:
Which of the following equations defines a line for which no points on the line lie in quadrant III?

A.\(y = –3x + 4\)

B.\(y = 3x + 4\)

C.\(y= \frac{X}{3}+4\)

D.\(y = –3x – 4\)

E. \(y = 3x – 4\)


Conventional: find the intercepts and graph the line
Attachment:
lines.png

Set x equal to zero, then y equal to zero to find x- and y-intercepts.
These equations are in point slope form, and the numbers aren't bad.

A. \(y = –3x + 4\)
\(x = 0: y = 4\)
\(y = 0: 3x = 4, x = \frac{4}{3}\)
POINTS \((0,4) , (\frac{4}{3}, 0)\)

B. \(y = 3x + 4\)
\(x = 0: y = 4\)
\(y = 0: -3x = 4, x = -\frac{3}{4}\)
POINTS \((0, 4) and (-\frac{3}{4}, 0)\)

C. \(y= \frac{X}{3}+4\)
\(x = 0: y = 4\)
\(y = 0: \frac{x}{3} = -4, x = -12\)
POINTS \((0, 4) and (-12, 0)\)

D. \(y = –3x – 4\)
\(x = 0: y = -4\)
\(y = 0: 3x = -4, x = -\frac{4}{3}\)
POINTS (\(0, -4) and ( -\frac{4}{3}, 0)\)

E. \(y = 3x – 4\)
\(x = 0: y = -4\)
\(y = 0: 3x = 4, x = \frac{4}{3}\)
POINTS \((0, -4) and (\frac{4}{3}, 0)\)

See diagram. Only A avoids Q III.

ANSWER A

Sketch generally: watch slope and y-intercept
This way is a lot faster: Figure out whether the line's slope and y-intercept should be positive or negative.

Sketch the two absolute cases: a line with a positive slope through the origin, and one with a negative slope through the origin. Go from there.
Attachment:
lines2.png

1. Sketch a line with a positive slope that passes through the origin: lines with positive slopes always pass through Quadrants I and III
Reject this one. We need to avoid Quadrant III. We need a negative slope

2) Sketch a line with a negative slope that passes through the origin
Lines with negative slopes always pass through Quadrants II and IV. How to avoid Q III?

3) Shift the line with the negative slope from the origin so that it does not pass through Q III
Note the y-intercept: it is positive

4) We need: a line with NEGATIVE slope and POSITIVE y-intercept

Check the options: Answers, B, C, and E are eliminated. Their slopes are positive

A. \(y = –3x + 4\)
Slope is -3
y-intercept is 4 (if x = 0, y = 4) KEEP

D. \(y = –3x – 4\)
Slope is -3
y-intercept is -4 (if x = 0, y = -4) REJECT

ANSWER A


fantastic reply
GMAT Club Bot
Re: Which of the following equations defines a line for which no points on   [#permalink] 02 Feb 2019, 20:48
Display posts from previous: Sort by

Which of the following equations defines a line for which no points on

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  


Copyright

GMAT Club MBA Forum Home| About| Terms and Conditions and Privacy Policy| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.