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Which of the following fractions has a decimal equivalent that is a te
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Which of the following fractions has a decimal equivalent that is a terminating decimal? A. 10/189 B. 15/196 C. 16/225 D. 25/144 E. 39/128
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Originally posted by ankur55 on 09 Jul 2009, 10:29.
Last edited by Bunuel on 01 Feb 2019, 01:01, edited 2 times in total.
Renamed the topic and edited the question.




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Which of the following fractions has a decimal equivalent that is a te
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01 Oct 2013, 07:38
Which of the following fractions has a decimal equivalent that is a terminating decimal?A. 10/189 B. 15/196 C. 16/225 D. 25/144 E. 39/128 THEORY:Reduced fraction \(\frac{a}{b}\) (meaning that fraction is already reduced to its lowest term) can be expressed as terminating decimal if and only \(b\) (denominator) is of the form \(2^n5^m\), where \(m\) and \(n\) are nonnegative integers. For example: \(\frac{7}{250}\) is a terminating decimal \(0.028\), as \(250\) (denominator) equals to \(2*5^2\). Fraction \(\frac{3}{30}\) is also a terminating decimal, as \(\frac{3}{30}=\frac{1}{10}\) and denominator \(10=2*5\). Note that if denominator already has only 2s and/or 5s then it doesn't matter whether the fraction is reduced or not. For example \(\frac{x}{2^n5^m}\), (where x, n and m are integers) will always be the terminating decimal. We need reducing in case when we have the prime in denominator other then 2 or 5 to see whether it could be reduced. For example fraction \(\frac{6}{15}\) has 3 as prime in denominator and we need to know if it can be reduced. BACK TO THE QUESTION:Only option E (when reduced to its lowest form) has the denominator of the form \(2^n5^m\): 39/128=39/2^7. Answer: E. Questions testing this concept:http://gmatclub.com/forum/doesthedeci ... 89566.htmlhttp://gmatclub.com/forum/anydecimalt ... 01964.htmlhttp://gmatclub.com/forum/ifabcdan ... 25789.htmlhttp://gmatclub.com/forum/700question94641.htmlhttp://gmatclub.com/forum/isrs2isa ... 91360.htmlhttp://gmatclub.com/forum/plexplain89566.htmlhttp://gmatclub.com/forum/whichofthe ... 88937.html
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Re: Which of the following fractions has a decimal equivalent that is a te
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09 Jul 2009, 10:56
The answer is E.
For a fraction to be a terminating decimal the denominator can contain only the prime factors 2 and/or 5 i.e. the denominator should be in the form \(2^a5^b\)
Looking at each denominator.
A. 189 has the prime factor 3 so the fraction is not a terminating decimal. B. 196 has the prime factor 7 so the fraction is not a terminating decimal. C. 225 has the prime factor 3 so the fraction is not a terminating decimal. D. 144 has the prime factor 3 so the fraction is not a terminating decimal. E. 128 has the prime factor 2 only and can be written in the form \(2^75^0\) which makes the fraction a terminating decimal.




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Re: Which of the following fractions has a decimal equivalent that is a te
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09 Jul 2009, 11:28
One important point: you should look at numerator as well, as it can simplify denominator. For example, \(18/225\) is a terminating decimal: \(18/225=\frac{3*3*2}{3*3*5*5}=\frac{2}{5*5}\). However, this problem doesn't try to trick you this way.



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Re: Which of the following fractions has a decimal equivalent that is a te
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07 Sep 2013, 06:48
akankshasoneja wrote: salsal wrote: Which of the following fractions has a decimal equivalent that is a terminating decimal?
a) 10/189 b) 15/196 c) 16/225 d) 25/144 e) 39/128 is there any simple method to find it? Denominators of options a,c,d contains powers of 3...numerators of these options when divided by 3 will have nonterminating decimals Denominator of option b contains power of 7...numerator 15 when divided by 7 will give non terminating decimal Option E has denominator in powers of 2...so when 39 divided by 2 will give a terminating decimal Hope it helps



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Which of the following fractions has a decimal equivalent that is a te
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07 Sep 2013, 09:13



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Re: Which of the following fractions has a decimal equivalent that is a te
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07 Sep 2013, 10:07
You can solve this question in less than 30 seconds if you understand the concept of terminating decimal. The denominator must have only power's of 2 or 5 in the denominator no other powers ( if it has any other prime factors like 3,7, etc it won't be terminating). 2's and 5's can be in any possible combination but it must only have 2's and 5's
a) 10/189
denominator sum of digits is 18 so its divisible by 3 eliminate
b) 15/196
This has a prime factor of 7 when do the prime factorization of the denominator.. Eliminate
c) 16/225
denominator sum of digits is 9 so its divisible by 3 eliminate
d) 25/144
denominator sum of digits is 9 so its divisible by 3 eliminate
e) 39/128 Jackpot Correct answer



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Re: Which of the following fractions has a decimal equivalent that is a te
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07 Sep 2013, 10:13
fozzzy wrote: You can solve this question in less than 30 seconds if you understand the concept of terminating decimal. The denominator must have only power's of 2 or 5 in the denominator no other powers ( if it has any other prime factors like 3,7, etc it won't be terminating). 2's and 5's can be in any possible combination but it must only have 2's and 5's
This is true if a fraction is reduced to its lowest term. Consider this: the denominator of 3/30 has other primes than 2 or 5, but 3/30 IS a terminating decimal because 3 in the denominator gets reduced: 3/30=1/10=0.1. Hope it's clear.
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Re: Which of the following fractions has a decimal equivalent that is a te
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01 Oct 2013, 19:02
Bunuel wrote: salsal wrote: Which of the following fractions has a decimal equivalent that is a terminating decimal?
a) 10/189 b) 15/196 c) 16/225 d) 25/144 e) 39/128 THEORY:Reduced fraction \(\frac{a}{b}\) (meaning that fraction is already reduced to its lowest term) can be expressed as terminating decimal if and only \(b\) (denominator) is of the form \(2^n5^m\), where \(m\) and \(n\) are nonnegative integers. For example: \(\frac{7}{250}\) is a terminating decimal \(0.028\), as \(250\) (denominator) equals to \(2*5^2\). Fraction \(\frac{3}{30}\) is also a terminating decimal, as \(\frac{3}{30}=\frac{1}{10}\) and denominator \(10=2*5\). Note that if denominator already has only 2s and/or 5s then it doesn't matter whether the fraction is reduced or not. For example \(\frac{x}{2^n5^m}\), (where x, n and m are integers) will always be the terminating decimal. We need reducing in case when we have the prime in denominator other then 2 or 5 to see whether it could be reduced. For example fraction \(\frac{6}{15}\) has 3 as prime in denominator and we need to know if it can be reduced. BACK TO THE QUESTION:Only option E (when reduced to its lowest form) has the denominator of the form \(2^n5^m\): 39/128= 39/2^7. Answer: E. Questions testing this concept:doesthedecimalequivalentofpqwherepandqare89566.htmlanydecimalthathasonlyafinitenumberofnonzerodigits101964.htmlifabcdandeareintegersandp2a3bandq2c3d5eispqaterminatingdecimal125789.html700question94641.htmlisrs2isaterminatingdecimal91360.htmlplexplain89566.htmlwhichofthefollowingfractions88937.htmlHope it helps. I'm confused, 128 is 2^7, you said it had to be 2^n*5^m....there is no 5^m in 128



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Re: Which of the following fractions has a decimal equivalent that is a te
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02 Oct 2013, 03:18
AccipiterQ wrote: Bunuel wrote: salsal wrote: Which of the following fractions has a decimal equivalent that is a terminating decimal?
a) 10/189 b) 15/196 c) 16/225 d) 25/144 e) 39/128 THEORY:Reduced fraction \(\frac{a}{b}\) (meaning that fraction is already reduced to its lowest term) can be expressed as terminating decimal if and only \(b\) (denominator) is of the form \(2^n5^m\), where \(m\) and \(n\) are nonnegative integers. For example: \(\frac{7}{250}\) is a terminating decimal \(0.028\), as \(250\) (denominator) equals to \(2*5^2\). Fraction \(\frac{3}{30}\) is also a terminating decimal, as \(\frac{3}{30}=\frac{1}{10}\) and denominator \(10=2*5\). Note that if denominator already has only 2s and/or 5s then it doesn't matter whether the fraction is reduced or not. For example \(\frac{x}{2^n5^m}\), (where x, n and m are integers) will always be the terminating decimal. We need reducing in case when we have the prime in denominator other then 2 or 5 to see whether it could be reduced. For example fraction \(\frac{6}{15}\) has 3 as prime in denominator and we need to know if it can be reduced. BACK TO THE QUESTION:Only option E (when reduced to its lowest form) has the denominator of the form \(2^n5^m\): 39/128= 39/2^7. Answer: E. Questions testing this concept:doesthedecimalequivalentofpqwherepandqare89566.htmlanydecimalthathasonlyafinitenumberofnonzerodigits101964.htmlifabcdandeareintegersandp2a3bandq2c3d5eispqaterminatingdecimal125789.html700question94641.htmlisrs2isaterminatingdecimal91360.htmlplexplain89566.htmlwhichofthefollowingfractions88937.htmlHope it helps. I'm confused, 128 is 2^7, you said it had to be 2^n*5^m....there is no 5^m in 128 Yes, it is 128 = 2^7*5^0.
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Re: Which of the following fractions has a decimal equivalent that is a te
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02 Oct 2013, 07:12
Bunuel wrote: AccipiterQ wrote:
I'm confused, 128 is 2^7, you said it had to be 2^n*5^m....there is no 5^m in 128
Yes, it is 128 = 2^7*5^0. So ANY number with a 2^x or 5^x (where x is greater than or equal to 1) will fall into this then? I'm confused though, so 6/15 a terminating decimal, because 15 is 5^1*3^1*2^0, but then why is 16/225 is not terminating? It follows the same pattern; 225 is 5^2*3^2*2^0



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Re: Which of the following fractions has a decimal equivalent that is a te
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02 Oct 2013, 08:35
AccipiterQ wrote: Bunuel wrote: AccipiterQ wrote:
I'm confused, 128 is 2^7, you said it had to be 2^n*5^m....there is no 5^m in 128
Yes, it is 128 = 2^7*5^0. So ANY number with a 2^x or 5^x (where x is greater than or equal to 1) will fall into this then? I'm confused though, so 6/15 a terminating decimal, because 15 is 5^1*3^1*2^0, but then why is 16/225 is not terminating? It follows the same pattern; 225 is 5^2*3^2*2^0 Please read again: whichofthefollowingfractionshasadecimalequivalent159322.html#p12646736/15=6/(3*5) is a terminating decimal because extra 3 in the denominator is reduced and we get 2/5 (the denominator is in the form of 2^n*5^m). 16/225=16/(3^2*5^2) is not a terminating decimal because extra 3^2 in the denominator is not reduced to get the denominator in the form of 2^n*5^m. Hope it's clear.
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Re: Which of the following fractions has a decimal equivalent that is a te
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28 Sep 2016, 16:22
salsal wrote: Which of the following fractions has a decimal equivalent that is a terminating decimal?
a) 10/189 b) 15/196 c) 16/225 d) 25/144 e) 39/128 NOTE: this is one of those questions that require us to check/test each answer choice. In these situations, always check the answer choices from E to A, because the correct answer is typically closer to the bottom than to the top. For more on this strategy, see my article: http://www.gmatprepnow.com/articles/han ... questions Cheers, Brent
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Re: Which of the following fractions has a decimal equivalent that is a te
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01 Mar 2017, 00:59
If numerator and denominator in fraction doesn’t have any common factor and the denominator has a prime factor except 2 and 5, then it is going to be non terminating decimal. Out of every option only Option E has 2 as the prime factor. Rest all have 3also. Hence option E s the answer
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Re: Which of the following fractions has a decimal equivalent that is a te
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01 Mar 2017, 02:08
salsal wrote: Which of the following fractions has a decimal equivalent that is a terminating decimal?
a) 10/189 b) 15/196 c) 16/225 d) 25/144 e) 39/128 Check out this post for a detailed discussion on terminating decimals: https://www.veritasprep.com/blog/2013/1 ... thegmat/
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Re: Which of the following fractions has a decimal equivalent that is a te
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13 Mar 2018, 17:01
salsal wrote: Which of the following fractions has a decimal equivalent that is a terminating decimal?
a) 10/189 b) 15/196 c) 16/225 d) 25/144 e) 39/128 A decimal will terminate when the equivalent fraction in lowest terms has a denominator that breaks down to primes of 2’s only, 5’s only, or both 2’s and 5’s only. Looking at our answer choices we see that 39/128 is a terminating decimal since 128 = 2^7. Answer: E
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Re: Which of the following fractions has a decimal equivalent that is a te
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13 Mar 2019, 23:00
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