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could you please also share how will even consecutive numbers be in term of x?

Ajaykumar2054
when ever we get consecutive integer its best to suppose the integers as X-1, X, X+1 form so that we can directly find sum as 3x.

in this case there is 5 consecutive odd integer, hence lets say those integers are x-4,x-2,x,x+2 and x+4 which means sum=5x
also lets say 7 consecutive integers be y-6,y-4,y-2,y,y+2,y+4,y+6 which means sum=7y

since we know 7y=5x we can conclude that the sum must be multiple of 7 and 5 which means multiple of 35.
now if we go through answer choices, we see option b, c and,e satisfies the criteria, and since sum of odd number of odd numbers can not be positive, we can eliminate b and c. finally left with option e as answer choice.
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in case of even consecutive integer also you can follow the same approach. let me help you out with an example.

if the sum of 5 consuctitve even integer is 70, what is the smallest integer in that list?
solution; let list of 5 positive consecutive even integers be x-4,x-2,x,x+2,x+4
this means sum is 5x = 70
or x=14

hence the list of 5 consecutive integer becomes x-4,x-2,x,x+2,x+4 which means 10,12,14,16,18 (here i did x-4=14-4=10, x-2=14-2=12 and so on....)

hence the smallest number in list is 10.

i hope your doubt is cleared now, i'll be happy to help you out if you need further clarification
shubhim20
could you please also share how will even consecutive numbers be in term of x?

Ajaykumar2054
when ever we get consecutive integer its best to suppose the integers as X-1, X, X+1 form so that we can directly find sum as 3x.

in this case there is 5 consecutive odd integer, hence lets say those integers are x-4,x-2,x,x+2 and x+4 which means sum=5x
also lets say 7 consecutive integers be y-6,y-4,y-2,y,y+2,y+4,y+6 which means sum=7y

since we know 7y=5x we can conclude that the sum must be multiple of 7 and 5 which means multiple of 35.
now if we go through answer choices, we see option b, c and,e satisfies the criteria, and since sum of odd number of odd numbers can not be positive, we can eliminate b and c. finally left with option e as answer choice.
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Of the options given , sum of 5 odd numbers and sum of 7 odd numbers should be an odd number and hence B,C are out . The sum of 5 consecutive odd or even numbers should be a multiple of 5 since(x-2,x-4,x,x+2,x+4 =5x) .So A is out . We are left with D,E options .
Sum of 7 consecutive even or odd should be multiple of 7 . So the value we are looking for should be a multiple of both 5 ,7
D(215) divides by 5 but not by 7 and hence is out . E(525) is divisible by both and is the Answer.
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Any odd number can be written as:

N, N+2, N+4, N+6, N+8, N+10, N+12, N+14 (Only condition given for this is to be that N should be Odd)

Now lets take sum of 5 consecutive odd numbers= N+N+2+N+4+N+6+N+8= 5n+20
Similarly sum of 7 consecutive odd numbers= 7N+42

Now our answer is number satisfying both the given equations for an ODD value of N. Lets evaluate answer options

A. 49--->5n=49-20-->5n=29 Not possible (I am not checking 7n+42 here since 5n+42 is not matching)
B. 70--->5n=50 and 7n=28 N=10 and N=4 -->this is a TRAP answer, we will jump into this, Why is it not correct because for us to have this, N SHOULD BE ODD
C. 140--> 5n=120, n=24 NOT ODD
D.315-->5n=195, n=39, checking for 7n=173 n=Not an Integer, Its a fraction
E. 525--> 5n=505, n=101 similarly 7n=483, n=69 both N values are odd and satisfy equation

RIGHT ANSWER E

MORAL OF QUESTION: ESCAPE TRAP ANSWER OF &)
hfbamafan
Which of the following integers can be written as both the sum of 5 consecutive odd integers and 7 consecutive odd integers?

A. 49
B. 70
C. 140
D. 215
E. 525
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