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29 Dec 2020, 22:56
Kudos
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
70% (00:45) correct
30%
(01:50)
wrong
based on 43
sessions
History
Date
Time
Result
Not Attempted Yet
Which of the following is an equation of the circle that has its center at (4,2) in the standard (x,y) coordinate plane and has a diameter of 8 units?
(A) \((x – 4)^2 + (y – 2)^2 = 16\)
(B) \((x – 4)^2 + (y – 2)^2 = 64\)
(C) \((x – 2)^2 + (y – 4)^2 = 64\)
(D) \((x + 4)^2 + (y + 2)^2 = 8\)
(E) \((x + 4)^2 – (y + 2)^2 = –64\)
(A) \((x – 4)^2 + (y – 2)^2 = 16\)
(B) \((x – 4)^2 + (y – 2)^2 = 64\)
(C) \((x – 2)^2 + (y – 4)^2 = 64\)
(D) \((x + 4)^2 + (y + 2)^2 = 8\)
(E) \((x + 4)^2 – (y + 2)^2 = –64\)
30 Dec 2020, 01:01
Kudos
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The formula for the equation of a circle is \((x – h)^2+ (y – k)^2 = r^2\), where \((h, k) \) represents the coordinates of the center of the circle, and \(r\) represents the radius of the circle.
center at \((4,2)\) and diameter\(=8\); radius\(=4\)
Substitute the values in the above equation;
\((x-4)^2+(y-2)^2=4^2=16\)
IMO Ans A
center at \((4,2)\) and diameter\(=8\); radius\(=4\)
Substitute the values in the above equation;
\((x-4)^2+(y-2)^2=4^2=16\)
IMO Ans A
30 Dec 2020, 01:07
Kudos
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Quote:
As the distance between the two given points (4,1) and (x,y) is 4units(ie. radius), applying distance formula or Pythagoras Th.
(x-4)^2 + (y-2)^2 = 4^2 = 16
A is correct
