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10 Nov 2020, 02:08
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
91% (00:55) correct
9%
(01:16)
wrong
based on 149
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Which of the following is equal to \(\frac{4t}{6} * \frac{-3}{t-3}\)
(A) \(\frac{2t}{t+3}\)
(B) \(\frac{4t-3}{6t-18}\)
(C) \(\frac{3t}{18}\)
(D) \(\frac{-2t}{t-3}\)
(E) \(\frac{t+4}{3}\)
(A) \(\frac{2t}{t+3}\)
(B) \(\frac{4t-3}{6t-18}\)
(C) \(\frac{3t}{18}\)
(D) \(\frac{-2t}{t-3}\)
(E) \(\frac{t+4}{3}\)
10 Nov 2020, 11:11
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Sajjad1994
Re-arranging the terms, we \(\frac{4 * 3}{6} * \frac{-t}{t - 3} = \frac{-2t}{t - 3}\)
Option D
Arun Kumar
11 Nov 2020, 01:32
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I always get confused with negatives, any suggestions on that? For this, I just subbed T = 4, which gave me the answer -8, and then quickly scanned for which option would provide the same. Got D.
