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A
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Difficulty:
35%
(medium)
Question Stats:
67% (01:46) correct
33%
(02:32)
wrong
based on 222
sessions
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Which of the following is equivalent to \(\frac{(2b)^{-1} - 2^{-1}b}{b^{-1} + 1^{-1}}\) ?
A. \(\frac{1 - b}{2}\)
B. \(\frac{b - 1}{2}\)
C. \(\frac{b^2 - 1}{2b}\)
D. \(\frac{1 - b^2}{2b}\)
E. \(\frac{2b}{1 - b^2}\)
Answer choices.JPG [ 3.44 KiB | Viewed 4746 times ]
Which of the following.JPG [ 12.21 KiB | Viewed 4739 times ]
A. \(\frac{1 - b}{2}\)
B. \(\frac{b - 1}{2}\)
C. \(\frac{b^2 - 1}{2b}\)
D. \(\frac{1 - b^2}{2b}\)
E. \(\frac{2b}{1 - b^2}\)
Attachment:
Answer choices.JPG [ 3.44 KiB | Viewed 4746 times ]
Attachment:
Which of the following.JPG [ 12.21 KiB | Viewed 4739 times ]
20 Jan 2020, 18:10
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Option A
Option A
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EE869B9C-A79C-4EC9-9BEF-64915DE1C157.jpeg [ 995.16 KiB | Viewed 5139 times ]
21 Jan 2020, 09:43
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Solution
To find
We need to determine
- • The value of the given expression
Approach and Working out
Numerator of the given expression = \((2b)^{-1} – 2^{-1} b = \frac{1}{2b} – \frac{b}{2} = \frac{(1}{b – b)/2} = \frac{(1 – b^2)}{2b}\)
Denominator of the given expression = \(b^{-1} + 1^{-1} = \frac{1}{b} + 1 = \frac{(1 + b)}{b}\)
- • Hence, the value of the expression = \(\frac{(1 – b^2)}{2b} * \frac{b}{(1 + b)} = \frac{(1 – b)}{2}\)
Thus, option A is the correct answer.
Correct Answer: Option A
