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mrinal2100
Which of the following quantities is the largest?

(A) \(\sqrt{2}\)

(B) \(\sqrt[3]{3}\)

(C) \(\sqrt[4]{5}\)

(D) \(\sqrt[5]{5}\)

(E) \(\sqrt[6]{6}\)

The question shows another answer choice for C, but I second your approach Karishma

Now, let's assume the question as is

2^30, 3^20 and 5^15

In this case, I assume it would be a matter of setting all exponents to GCF and compare the bases

So we would end up with 64^5, 81^5, 64^5

Clearly now B is the winner here

Kudos rain!

Cheers!
J :)

Edited option C. It should be as written in Karishma's post.
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jlgdr

Now, let's assume the question as is

2^30, 3^20 and 5^15

In this case, I assume it would be a matter of setting all exponents to GCF and compare the bases

So we would end up with 64^5, 81^5, 64^5

Clearly now B is the winner here

Kudos rain!

Cheers!
J :)

2^30, 3^20 and 5^15
Yes, you can get the common power of 5

64^5, 81^5 and 125^5

So 5^15 is greatest here.
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mrinal2100
sorry guys for the wron quote but the choices were
a)2(pow)(1/2)
b)3(pow)(1/3)
c)4(pow)(1/4)
d)5(pow)(1/5)
e)6(pow)(1/6)

its not 6*(sqroot of 6)

So I am assuming that the choices are:
\(2^{\frac{1}{2}}, 3^{\frac{1}{3}}, 4^{\frac{1}{4}}, 5^{\frac{1}{5}}, 6^{\frac{1}{6}}\)

Since fractional powers are a pain, let me multiply all the powers by 60 (LCM) to make them manageable.

\(2^{30}, 3^{20}, 4^{15} ( = 2^{30}), 5^{12}, 6^{10}\)
Bases and powers, both are different. To compare, we need to make one of them the same.

\(2^{30} = 8^{10}\)
\(3^{20} = 9^{10}\)
\(6^{10}\)

Obviously, out of these three, \(9^{10}\) is greatest.

Now we just need to compare \(3^{20}\) with \(5^{12}\)
\(3^{20} = 243^{4}\)
\(5^{12} = 125^{4}\)

\(3^{20} ( = 3^{\frac{1}{3}})\) is the greatest.


I Karishma - it's very clear and simple until the end. To compare 3^20 with 5^12, it seems that we need to know what 3^16 and 5^8 are. Isn't 3^16 a uncommon number to memorize? Or is this expected for the gmat / there is an easier way to compare? Thanks so much!
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mrinal2100
sorry guys for the wron quote but the choices were
a)2(pow)(1/2)
b)3(pow)(1/3)
c)4(pow)(1/4)
d)5(pow)(1/5)
e)6(pow)(1/6)

its not 6*(sqroot of 6)

So I am assuming that the choices are:
\(2^{\frac{1}{2}}, 3^{\frac{1}{3}}, 4^{\frac{1}{4}}, 5^{\frac{1}{5}}, 6^{\frac{1}{6}}\)

Since fractional powers are a pain, let me multiply all the powers by 60 (LCM) to make them manageable.

\(2^{30}, 3^{20}, 4^{15} ( = 2^{30}), 5^{12}, 6^{10}\)
Bases and powers, both are different. To compare, we need to make one of them the same.

\(2^{30} = 8^{10}\)
\(3^{20} = 9^{10}\)
\(6^{10}\)

Obviously, out of these three, \(9^{10}\) is greatest.

Now we just need to compare \(3^{20}\) with \(5^{12}\)
\(3^{20} = 243^{4}\)
\(5^{12} = 125^{4}\)

\(3^{20} ( = 3^{\frac{1}{3}})\) is the greatest.


I Karishma - it's very clear and simple until the end. To compare 3^20 with 5^12, it seems that we need to know what 3^16 and 5^8 are. Isn't 3^16 a uncommon number to memorize? Or is this expected for the gmat / there is an easier way to compare? Thanks so much!

It is not \(3^{16}\) that you need to remember.

When you end up comparing \(3^{20}\) and \(5^{12}\), try to raise the 2 numbers to the same power.

In this case the common GCD of 20 and 12 is 4.

Thus \(3^{20}=(3^5)^4\) and

\(5^{12} = (5^3)^4\)

Giving you the 2 values as \(243^4\) and \(125^4\). So now can easily see that the 2 numbers are raised to the same power but with a differnet base giving you \(3^{20} > 5^{12}\)
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mrinal2100
Which of the following quantities is the largest?

(A) \(\sqrt{2}\)

(B) \(\sqrt[3]{3}\)

(C) \(\sqrt[4]{4}\)

(D) \(\sqrt[5]{5}\)

(E) \(\sqrt[6]{6}\)

first multiply all the powers by 60 cus fractions are confusing
\(2^{30}, 3^{20}, 4^{15}, 5^{12}, 6^{10}\)

Now, the easiest way as per me to do this would be to start with two powers; compare them and proceed ahead.
quicky browsing through the ans choices I can estimate the answer must be either A or B so let's start with them.

we need to get the bases or the powers equal to be able to equate them; lets make the powers equal
\(2^{30} \)can be written as \((2^{3})^{10}\) and \(3^{20}\) can be written as \((3^{2})^{10}\)
\(2^3<3^2 \)hence B is larger

now if you want to test further you could, it'll be easier now to compare the remaining three powers with 3^20 since we have already established that it's higher than one answer choice (A)

\(3^{20} =(3^{4})^{5}\)
\(4^{15} = (4^{3})^{5}\)
again \(3^4> 4^3\)

we can check the rest of the cases the same way.

-- adding a shorter way --

once we get here:
\(2^{30}, 3^{20}, 4^{15}, 5^{12}, 6^{10}\)

we can take the power of 5 common from all except 5^12

ie.\( (2^6)^5, (3^4)^5, (4^3)^5, (6^2)^5\)
now we just have to compare 2^6 with 3^4 and similarly for rest
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My approach was comparing each answer choice:

A) (2^1/2)^6 = 2^3 = 8, whereas (6^1/6)^6 = 6, so A) is greater than E).

B) (3^1/3)^6 = 3^2 = 9, so B) is greater than A).

Now A) is equal to C) since (2^1/2)^4 = 4 and (4^1/4)^4 = 4, so C) is also smaller than B).

Finally, we compare A) to D) by raising to the power of 10: (2^1/2)^10 = 2^5 = 32 and (5^1/5)^10 = 25, so D) is smaller than A), and since A) is smaller than B), D) is also smaller than B).

We can conclude that B) is the biggest number.
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