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Which of the following sets includes ALL of the solutions of
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16 Jul 2003, 01:02
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50% (02:23) correct 50% (01:02) wrong based on 14 sessions
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Which of the following sets includes ALL of the solutions of x that will satisfy the equation:
x тАУ 2  x тАУ 3 = x тАУ 5?
(A) {6, 5, 0, 1, 7, 8}
(B) {4, 2, 0, 10/3, 4, 5}
(C) {4, 0, 1, 4, 5, 6}
(D) {1, 10/3, 3, 5, 6, 8}
(E) {2, 1, 1, 3, 4, 5} == Message from the GMAT Club Team == THERE IS LIKELY A BETTER DISCUSSION OF THIS EXACT QUESTION. This discussion does not meet community quality standards. It has been retired. If you would like to discuss this question please repost it in the respective forum. Thank you! To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative  Verbal Please note  we may remove posts that do not follow our posting guidelines. Thank you.
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AkamaiBrah Former Senior Instructor, Manhattan GMAT and VeritasPrep Vice President, Midtown NYC Investment Bank, Structured Finance IT MFE, Haas School of Business, UC Berkeley, Class of 2005 MBA, Anderson School of Management, UCLA, Class of 1993



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D.
Simple, but effective way  I found that 6 is the solution. so, I eliminated wrong answers. then I tryed 0 in the remaining ones and ended up this D.



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Any more tries?
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AkamaiBrah Former Senior Instructor, Manhattan GMAT and VeritasPrep Vice President, Midtown NYC Investment Bank, Structured Finance IT MFE, Haas School of Business, UC Berkeley, Class of 2005 MBA, Anderson School of Management, UCLA, Class of 1993



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I have just solved the equation and got only 4 and 6.



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Ans is C.
Take 2 < x < 3.
So the equation will be,
x 2 +x 3 = x +5.
So, 3x = 10.
So, x = 10/3 not possible.
Take 3 < x < 5
x =4,
Take x >5
So x = 6.



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evensflow wrote: Ans is C.
Take 2 < x < 3.
So the equation will be,
x 2 +x 3 = x +5.
So, 3x = 10.
So, x = 10/3 not possible.
Take 3 < x < 5 x =4,
Take x >5
So x = 6.
Your solution has the proper approach. You forgot to check x<2, but there is no solution in that interval so your answer is correct.
BTW, I composed the problem this way so that it would be somewhat timeconsuming to backsolve it (i.e., check all the answers).
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AkamaiBrah Former Senior Instructor, Manhattan GMAT and VeritasPrep Vice President, Midtown NYC Investment Bank, Structured Finance IT MFE, Haas School of Business, UC Berkeley, Class of 2005 MBA, Anderson School of Management, UCLA, Class of 1993



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Well i did for x <2 also on paper..
but felt lazy to type the answer as yes the soultion is not possible, since x = 6.



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Location: Uruguay

Sorry, I don┬┤t get it
In C, you have number 0, and that does not satisfy the equation, how can be right?



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MBA04 wrote: Sorry, I don┬┤t get it
In C, you have number 0, and that does not satisfy the equation, how can e right?
I asked for the set that contained all of the solutions, not the set where egvery member was a solution. The only solutions are 4 and 6. C has both of them.
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AkamaiBrah Former Senior Instructor, Manhattan GMAT and VeritasPrep Vice President, Midtown NYC Investment Bank, Structured Finance IT MFE, Haas School of Business, UC Berkeley, Class of 2005 MBA, Anderson School of Management, UCLA, Class of 1993



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Joined: 11 Nov 2003
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Location: Illinois

evensflow wrote: Ans is C.
Take 2 < x < 3.
So the equation will be,
x 2 +x 3 = x +5.
So, 3x = 10.
So, x = 10/3 not possible.
Take 3 < x < 5 x =4,
Take x >5
So x = 6.
Hi Akamai,
In the above approach, while selecting various range, should we consider one of the extreme as part of the range? For exampl, instead of range x > 5, should we consider x >= 5. So that just in case if we arrive at x = 5 then that can be considered valid solution? I know it is not applicable in this problem but what if the quation is designed that way?
Thanks



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If the solution is right on the value, then it will be a valid solution in both intervals (before and after) so >= is fine unless the variable is in the denominator and will equal zero. == Message from the GMAT Club Team == THERE IS LIKELY A BETTER DISCUSSION OF THIS EXACT QUESTION. This discussion does not meet community quality standards. It has been retired. If you would like to discuss this question please repost it in the respective forum. Thank you! To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative  Verbal Please note  we may remove posts that do not follow our posting guidelines. Thank you.
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Best,
AkamaiBrah Former Senior Instructor, Manhattan GMAT and VeritasPrep Vice President, Midtown NYC Investment Bank, Structured Finance IT MFE, Haas School of Business, UC Berkeley, Class of 2005 MBA, Anderson School of Management, UCLA, Class of 1993



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Re: Which of the following sets includes ALL of the solutions of
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23 Jan 2019, 06:37
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Re: Which of the following sets includes ALL of the solutions of
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23 Jan 2019, 06:37






